无法在wamp中使用假sendmail发送电子邮件

Pao*_*sas 3 php sendmail

我已经这样做了好几个小时并且无法让它工作,教程中的许多评论说它的功能就像一个魅力,但我无法真正做到这一点.

我已经完成了所有步骤http://blog.techwheels.net/send-email-from-localhost-wamp-server-using-sendmail/并阅读了所有其他用户遇到的问题的评论,并使用了回复的解决方案.

我在apache错误日志中看到的是这个

[Tue Nov 27 05:19:47 2012] [notice] Parent: Created child process 4120
[Tue Nov 27 05:19:47 2012] [warn] Init: Session Cache is not configured [hint: SSLSessionCache]
[Tue Nov 27 05:19:48 2012] [notice] Child 4120: Child process is running
[Tue Nov 27 05:19:48 2012] [notice] Child 4120: Acquired the start mutex.
[Tue Nov 27 05:19:48 2012] [notice] Child 4120: Starting 64 worker threads.
[Tue Nov 27 05:19:48 2012] [notice] Child 4120: Starting thread to listen on port 80.
[Tue Nov 27 05:19:48 2012] [notice] Child 4120: Starting thread to listen on port 80.
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我也在我的另一台计算机上尝试过,它有相同的错误日志.我已经禁用了防火墙,并严格按照教程中的步骤操作.

Che*_*kar 5

对不起,上一个答案.感谢大家的建议,以改善我的答案.这是我的答案:phpmailer有一个名为class.phpmailer.php的文件.然后在function smtpmailer($to, $from, $from_name, $subject, $body)代码中如下:

global $error;
$mail = new PHPMailer(); 
$mail->IsSMTP(); 
$mail->SMTPDebug = 0; 
$mail->SMTPAuth = true;  
$mail->SMTPSecure = 'ssl'; 
$mail->Host = 'smtp.gmail.com';
$mail->Port = 465; 
$mail->Username = 'gmailusername';  
$mail->Password = 'gmailpassword';           
$mail->SetFrom($from, $from_name);
$mail->Subject = $subject;
    $mail->IsHTML(True);
    $mail->Body=$body;
//$mail->Body = $body;
$mail->AddAddress($to);
if(!$mail->Send()) {
    $error = 'Mail error: '.$mail->ErrorInfo; 
    return false;
} else {
    $error = 'Message sent!';
    return true;
}
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然后只需调用您想要的函数: smtpmailer($to, $from, $headers, $subject, $message);

哦,在此之前确保启用了php_openssl扩展.

我希望我的回答很有帮助.:)