用python编写cgi脚本

Question

我试图在python3中使用它作为服务器运行一个cgi脚本:

from http.server import HTTPServer, CGIHTTPRequestHandler

port = 8080

httpd = HTTPServer(('', port), CGIHTTPRequestHandler)
print("Starting simple_httpd on port: " + str(httpd.server_port))
httpd.serve_forever()

但我收到以下错误:

Traceback (most recent call last):
  File "/usr/lib/python3.2/http/server.py", line 1110, in run_cgi
    os.execve(scriptfile, args, env)
OSError: [Errno 2] No such file or directory
localhost - - [21/Nov/2012 10:28:26] CGI script exit status 0x7f00

请帮忙.

Answer 1

希望这些帮助:1.检查您要执行的脚本是否可执行？如果它不是-rwx,则无法执行2.检查脚本的顶行,即#!.....如果这行没有正确指向你的python的文件夹,它仍然无法执行