C程序没有正确读取参数

Joh*_*rUK 2 c

我正在编写一个程序,我想接受命令行参数但是当我传递任何args时,它就好像始终调用start一样.我的代码如下.任何帮助表示赞赏.

//compile to iservices
// Ilkotech Services - C Core
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(int argc, char *argv[]) {
    if (argc < 2) {
        printf("Usage: %s start|shutdown|reload\n",argv[0]);
    }
    else {
        if (strcmp(argv[1],"start") != 0) {
            services_start();
        }
        else if (strcmp(argv[1],"shutdown") != 0) {
            services_shutdown();
        }
        else if (strcmp(argv[1],"reload") != 0) {
            services_reload();
        }
        else {
            printf("%s is not a valid argument\n",argv[1]);
            printf("Usage: %s start|shutdown|reload\n",argv[0]);
            exit(1);
        }
    }
    return 0;
}
int services_start() {
    printf("Started.\n");
    return 0;
}
int services_shutdown() {
    printf("Shutting down!\n");
    return 0;
}
int services_reload() {
    printf("Reloading services configuration.\n");
    return 0;
}
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md5*_*md5 7

strcmp 如果两个字符串都是等于,则返回0.

C11(n1570),§7.24.4.2的strcmp函数
strcmp函数返回一个整数大于,等于,或小于零,相应地作为字符串指向s1大于,等于,或小于字符串由指向s2.

一些程序员曾经调用以下宏:

#include <string.h>
#define cmp_strings(a, b) (strcmp(a, b) == 0)
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