将SELECT结果分配给field-symbol

Question

我是__CODE__编码的新手,我很困惑为什么注释掉的查询不起作用.

REPORT  z_hello_world_local.

TYPES:  BEGIN OF bkpf_type,
          xblnr          TYPE bkpf-xblnr,
        END OF bkpf_type.

DATA: t_bkpf                 TYPE TABLE OF bkpf_type.

FIELD-SYMBOLS:  <bkpf>        TYPE bkpf_type.


*This query does not work?
*SELECT xblnr
*      INTO CORRESPONDING FIELDS OF <bkpf> UP TO 1 ROWS
*      FROM bkpf
*      WHERE belnr = '1800001017'.
*    ENDSELECT.
*
DATA: t_xblnr TYPE bkpf-xblnr.

*This query works and in my head it is roughly the same thing.
SELECT SINGLE xblnr
      INTO t_xblnr
      FROM bkpf
      WHERE belnr = '1800001017'.


write 'Done'.

如果我运行注释掉的查询,我会收到错误:

运行时错误GETWA_NOT_ASSIGNED日期和时间
08/26/2009 19:54:19

短文字字段符号尚未分配.

任何帮助,将不胜感激.

Answer 1

我认为该网站隐藏了它在<>之间找到的任何代码.看起来你已经声明了一个字段符号,但我实际上看不到你的名字.

我假设(基于错误和我无法实际看到的代码片段)您试图直接将数据选择到字段符号中.你不能这样做.字段符号不是存储区域,它(基本上)是指针.

您可以执行以下操作之一:

data: wa_bkpf type bkpf_type.

select xblnr
  into corresponding fields of wa_bkpf
  up to 1 rows
  from bkpf
  where xblnr = '1800001017'.
endselect.

要么

field-symbols: <bkpf> type bkpf_type.
append initial line to t_bkpf assigning <bkpf>.
select xlbnr
  into corresponding fields <bkpf>
  up to 1 rows
  from bkpf
  where xblnr = '1800001017'.
endselect.

在这种情况下,您将字段符号指向已添加到内部表的新行.

要么

select xblnr
  into corresponding fields of table t_bkpf
  from bkpf
  where xlbnr = '1800001017'.

在这种情况下,您将检索匹配的所有文档并将它们直接放入内部表中.