如何在Django中按ID和Order By计数

Question

我在转换编写正确的Python脚本时遇到了麻烦,该脚本完成了我能完成的任务 MYSQL

下面是完成我想要的SQL查询.我python在GROUP BY声明中被绊倒的地方.

SELECT COUNT(story_id) AS theCount, `headline`, `url` from tracking
GROUP BY `story_id`
ORDER BY theCount DESC
LIMIT 20

这是我python到目前为止所拥有的.这可以很好地查询所有文章,但它缺少任何类型groupby()或order_by()基于COUNT.

articles = ArticleTracking.objects.all().filter(date__range=(start_date, end_date))[:20]

article_info = []    
for article in articles:
    this_value = {
        "story_id":article.story_id,
        "url":article.url,
        "headline":article.headline,
        }

    article_info.append(this_value)

Answer 1

正确的方法是使用聚合.

articles = ArticleTracking.objects.filter(date__range=(start_date, end_date))
articles = articles.values('story_id', 'url', 'headline').annotate(count = Count('story_id')).order_by('-count')[:20]

另请阅读Django中的聚合文档.

https://docs.djangoproject.com/en/dev/topics/db/aggregation/