No, (AB)* is not equals to A*B*
Run Code Online (Sandbox Code Playgroud)
(AB)* means ABABABABAB......AB AB序列(任意数量的时间).
A*B* means AAAA.....BBB......任意数量的A,后跟任意数量的B.在B之后,A不能出现.
路口-包括两个{ NULL string, AB }仅
例:
假设: A = xy和 B = z
(AB)* = xyzxyz.....xyz
A*B* = xyxyxyxy....zzzz....z
Run Code Online (Sandbox Code Playgroud)
交叉口 - 两者都包括在内{ NULL string, xyz}.
例:
假设 -
A = {a, b},
B = {c, d}
Run Code Online (Sandbox Code Playgroud)
然后,
(AB)* = ((a + b)(c + d))* , Its language
L = { ac, ab, acbd, acac, .....}
Run Code Online (Sandbox Code Playgroud)
注意:此语言中的所有字符串都是均匀的!
和
A*B* = (a + b)* (c + d)* , Its language
L = { a, b, c, d, ac, ad, bc, bd, acbd, addb,.........}
Run Code Online (Sandbox Code Playgroud)
注意:还包含奇数长度的字符串.