PHP Parse错误:语法错误,意外T_PUBLIC

Question

我在第3行的PHP代码中收到此错误,可能是什么错误？此代码取自frank在interactinet dot com上的 php手册用户注释

<?php

public function myMethod()
{
return 'test';
}

public function myOtherMethod()
{
return null;
}

if($val = $this->myMethod())
{
 // $val might be 1 instead of the expected 'test'
}

if( ($val = $this->myMethod()) )
{
// now $val should be 'test'
}

// or to check for false
if( !($val = $this->myMethod()) )
{
// this will not run since $val = 'test' and equates to true
}

// this is an easy way to assign default value only if a value is not returned:

if( !($val = $this->myOtherMethod()) )
{
$val = 'default'
}

?> 

Answer 1

该public关键字仅用于类中的函数/变量声明.由于您没有使用类,因此需要将其从代码中删除.