PHP语法错误.我瞎了吗？

Question

我有这个PHP代码,我收到此错误:解析错误:语法错误,意外'}',期待';' 在第120行的[文件位置]中

while($ array等)的行是第120行.

if($numrows != 0)
{
    do
    {
        //echo "<a href='approve.php?ref=" . $array['id'] . "'>Your '" . $array['keywords'] . "' article has been written and needs to be reviewed.</a>";
        //echo "<br />";
    } while($array = mysql_fetch_array($result)) //While there are still rows in the SELECT query.
}

想法？我必须失明.谢谢!

Answer 1

} while($array = mysql_fetch_array($result))

应该

} while($array = mysql_fetch_array($result));

这样做,而

顺便说一句,代码片段似乎应该使用while循环,除非你故意使用$array第一次的旧值.