在listview onclick中从数据库获取Id

Question

我有这个类,它从数据库中获取数据并显示在列表视图中.

有没有办法从数据库中获取Id并烘烤它？

现在吐司正在回归: android.database.sqlite.SQLiteCursor@4180c088

 public class AndroidSQLite extends Activity { 

 private SQLiteAdapter
 mySQLiteAdapter;

 @Override
 public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
     setContentView(R.layout.main);
     ListView listContent = (ListView)findViewById(R.id.contentlist);

     mySQLiteAdapter = new SQLiteAdapter(this);
     mySQLiteAdapter.openToRead();

     Cursor cursor = mySQLiteAdapter.queueAll();
     startManagingCursor(cursor);

     String[] from = new String[]{SQLiteAdapter.KEY_NOME,SQLiteAdapter.KEY_ID};
     int[] to = new int[]{R.id.text,R.id.id};

     SimpleCursorAdapter cursorAdapter =
      new SimpleCursorAdapter(this, R.layout.row, cursor, from, to);

     listContent.setAdapter(cursorAdapter);

     listContent.setOnItemClickListener(new OnItemClickListener() {
         public void onItemClick(AdapterView<?> parent, View view, int position,
                 long id) {
                //GET ID FROM DATABASE
                Toast.makeText(getBaseContext(), parent.getItemAtPosition(position).toString(), Toast.LENGTH_LONG).show();
                //THIS TOAST IS RETURNING "android.database.sqlite.SQLiteCursor@4180c088"
         }
     });

     mySQLiteAdapter.close();
 } }

Answer 1

只需使用以下id参数onItemClick():

Toast.makeText(getBaseContext(), id + "", Toast.LENGTH_LONG).show();

为了将来参考,您当前正在尝试将整个Cursor用作String,您要选择如下列:

Toast.makeText(getBaseContext(), parent.getItemAtPosition(position).getLong(0), Toast.LENGTH_LONG).show();

(对于SimpleCursorAdapter,第一列始终是_id列,因此getLong(0).)