基于时间戳按小时聚合数据

Question

这一定是一件普通的事情,但是我被困住了.

我有一些可以像这样简化的数据:

id    user    unixtime
-----------------------
1     dave    1335312057
2     dave    1335312058
3     steve   1335312128

等等

到目前为止,我只需要按天聚合,所以我一直在使用:

SELECT
 UNIX_TIMESTAMP(DATE(FROM_UNIXTIME(unixtime))) AS time,
 count(c.user) AS count
FROM core c
GROUP BY DATE(FROM_UNIXTIME(unixtime))

我已经尝试使用CONCAT与DATE和HOUR,但是不能让它按预期工作 - 任何想法？

Answer 1

SELECT
 DATE(FROM_UNIXTIME(unixtime)) as date,
 HOUR(FROM_UNIXTIME(unixtime)) AS hour,
 count(c.user) AS count
FROM core c
GROUP BY 1,2 

如果您希望将小时作为unix时间戳,请将此查询包装起来以获取它:

SELECT UNIX_TIMESTAMP(DATE_ADD(the_date, INTERVAL the_hour HOUR)), the_count
from (select
    DATE(FROM_UNIXTIME(unixtime)) as the_date,
    HOUR(FROM_UNIXTIME(unixtime)) as the_hour,
    count(c.user) AS the_count
    FROM core c
    GROUP BY 1,2 
) x

注意:the_在列名称上使用前缀以避免保留字的问题