Python解析IP地址和协议的日志文件

Question

这是我在stackoverflow上提出的第一个问题,我真的很期待成为这个社区的一员.我是程序新手,python是很多人推荐的第一个程序.

无论如何.我有一个日志文件,如下所示:

"No.","Time","Source","Destination","Protocol","Info"
"1","0.000000","120.107.103.180","172.16.112.50","TELNET","Telnet Data ..." 
"2","0.000426","172.16.112.50","172.16.113.168","TELNET","Telnet Data ..." 
"3","0.019849","172.16.113.168","172.16.112.50","TCP","21582 > telnet [ACK]" 
"4","0.530125","172.16.113.168","172.16.112.50","TELNET","Telnet Data ..." 
"5","0.530634","172.16.112.50","172.16.113.168","TELNET","Telnet Data ..."

我想用Python解析日志文件,使其看起来如下:

来自IP 135.13.216.191协议计数:(IMF 1)(SMTP 38)(TCP 24)(总计:63)

如果我使用列表并循环遍历它或词典/元组,我真的想要一些帮助解决这个问题的路径？

在此先感谢您的帮助!

Answer 1

您可以使用csv模块解析文件:

import csv

with open('logfile.txt') as logfile:
     for row in csv.reader(logfile):
         no, time, source, dest, protocol, info = row
         # do stuff with these

我不能完全说出你在问什么,但我想你想要:

import csv
from collections import defaultdict

# A dictionary whose values are by default (a
# dictionary whose values are by default 0)
bySource = defaultdict(lambda: defaultdict(lambda: 0))

with open('logfile.txt') as logfile:
     for row in csv.DictReader(logfile):
         bySource[row["Source"]][row["Protocol"]] += 1

for source, protocols in bySource.iteritems():
    protocols['Total'] = sum(protocols.values())

    print "From IP %s Protocol Count: %s" % (
        source,
        ' '.join("(%s: %d)" % item for item in protocols.iteritems())
    )

Answer 2

首先，您需要读入文本文件

# Open the file
file = open('log_file.csv')
# readlines() will return the data as a list of strings, one for each line
log_data = file.readlines()
# close the log file
file.close()

设置字典来保存您的结果

results = {}

现在迭代您的数据，一次一行，并将协议记录在字典中

for entry in log_data:
    entry_data = entry.split(',')
    # We are going to have a separate entry for each source ip
    # If we haven't already seen this ip, we need to make an entry for it
    if entry_data[2] not in results:
        results[entry_data[2]] = {'total':0}
    # Now check to see if we've seen the protocol for this ip before
    # If we haven't, add a new entry set to 0
    if entry_data[4] not in results[entry_data[2]]:
         results[entry_data[2]][entry_data[4]] = 0
    # Now we increment the count for this protocol
    results[entry_data[2]][entry_data[4]] += 1
    # And we increment the total count
    results[entry_data[2]]['total'] += 1

一旦你计算完所有内容，只需迭代你的计数并打印出结果

for ip in results:
    # Here we're printing a string with placeholders. the {0}, {1} and {2} will be filled
    # in by the call to format
    print "from: IP {0} Protocol Count: {1})".format(
        ip,
        # And finally create the value for the protocol counts with another format call
        # The square braces with the for statement inside create a list with one entry
        # for each entry, in this case, one entry for each protocol
        # We use ' '.join to join each of the counts with a string
        ' '.join(["({0}: {1})".format(protocol, results[ip][protocol] for protocol in results[ip])]))