在SQL Server 2008中按逗号分割字符串

Question

有两个字符串a和b

该a字符串包含逗号.我想用逗号分割一个字符串,然后遍历每个元素.

如果b字符串包含任何以逗号分割的元素将返回0

(例如:a = "4,6,8"; b = "R3799514"因为b字符串包含4所以返回0)

如何使用存储过程实现此目的？提前致谢!

我见过一个split函数:

CREATE FUNCTION dbo.Split(@String varchar(8000), @Delimiter char(1))     
returns @temptable TABLE (items varchar(8000))     
as     
begin     
declare @idx int     
declare @slice varchar(8000)     

select @idx = 1     
    if len(@String)<1 or @String is null  return     

while @idx!= 0     
begin     
    set @idx = charindex(@Delimiter,@String)     
    if @idx!=0     
        set @slice = left(@String,@idx - 1)     
    else     
        set @slice = @String     

    if(len(@slice)>0)
        insert into @temptable(Items) values(@slice)     

    set @String = right(@String,len(@String) - @idx)     
    if len(@String) = 0 break     
end 
return     
end

select top 10 * from dbo.split('Chennai,Bangalore,Mumbai',',')

Answer 1

以下将工作 -

DECLARE @A VARCHAR (100)= '4,5,6'
DECLARE @B VARCHAR (100)= 'RXXXXXX'
DECLARE @RETURN_VALUE BIT = 1 --DEFAULT 1


SELECT items
INTO #STRINGS 
FROM dbo.split(@A,',')

IF EXISTS(SELECT 1 FROM #STRINGS S WHERE CHARINDEX(items, @B) > 0)
SET @RETURN_VALUE = 0

PRINT @RETURN_VALUE

DROP TABLE #STRINGS

您也可以使用CONTAINS而不是CHARINDEX -

IF EXISTS(SELECT 1 FROM #STRINGS S WHERE CONTAINS(items, @B))
SET @RETURN_VALUE = 0