Mysql Like Syntax

Question

快速提问:mysqli_escape_string如何包含在like子句中的变量？

"SELECT * FROM table WHERE name LIKE '%". %s . "%'"    

要么

"SELECT * FROM table WHERE name like '%"."%s"."%'"

不工作.

谢谢!

Answer 1

$value = mysql_real_escape_string($_POST["terms"]);
$query = "SELECT * FROM table WHERE name LIKE '%".$value."%'";

或者你可以用这样的sprintf实现这个:

$query = sprintf("SELECT * FROM table WHERE name LIKE '%s'", "%".$value."%");