使用SQLCommand插入C#

Question

将数据插入数据库的最佳方法是什么？

这就是我所拥有的,但这是错的..

cmd.CommandText = "INSERT INTO klant(klant_id,naam,voornaam) VALUES(@param1,@param2,@param3)";

cmd.Parameters.Add(new SqlParameter("@param1", klantId));
cmd.Parameters.Add(new SqlParameter("@param2", klantNaam));
cmd.Parameters.Add(new SqlParameter("@param3", klantVoornaam));

该函数将数据添加到listBox中

http://www.pictourl.com/viewer/37e4edcf (link is dead)

但没有进入数据库..

http://www.pictourl.com/viewer/4d5721fc (link is dead)

全功能:

private void Form1_Load(object sender, EventArgs e)
{            
    conn2 = new SqlConnection();
    conn2.ConnectionString = ConfigurationManager.ConnectionStrings["connSpionshopString"].ConnectionString;
}

private void button2_Click(object sender, EventArgs e)
{         
    string sqlCmd = "SELECT naam,voornaam,klant_id FROM klant;";
    SqlCommand cmd = new SqlCommand(sqlCmd, conn2);

    conn2.Open();

    using(SqlDataReader reader = cmd.ExecuteReader())
    {
        while (reader.Read())
        {
            listBox2.Items.Add(reader.GetString(0) + " " + reader.GetString(1) + "  (" + reader.GetInt16(2) + ")");
        }  
    }
    conn2.Close();
}

private void button4_Click(object sender, EventArgs e)
{
    int klantId = Convert.ToInt32(textBox1.Text);
    string klantNaam = textBox2.Text;
    string klantVoornaam = textBox3.Text;

    conn2.Open();

    SqlCommand cmd = new SqlCommand();
    cmd.Connection = conn2;
    cmd.CommandText = "INSERT INTO klant(klant_id, naam, voornaam)   VALUES(@param1,@param2,@param3)";

    cmd.Parameters.AddWithValue("@param1", klantId);
    cmd.Parameters.AddWithValue("@param2", klantNaam);
    cmd.Parameters.AddWithValue("@param3", klantVoornaam);

    cmd.ExecuteNonQuery(); 

    conn2.Close();
}

Answer 1

尝试确认数据库中每个参数的数据类型(SqlDbType)并以这种方式执行;

 using(SqlConnection connection = new SqlConnection(ConfigurationManager.ConnectionStrings["connSpionshopString"].ConnectionString))
 {
            connection.Open();
            string sql =  "INSERT INTO klant(klant_id,naam,voornaam) VALUES(@param1,@param2,@param3)";
            using(SqlCommand cmd = new SqlCommand(sql,connection)) 
            {
                  cmd.Parameters.Add("@param1", SqlDbType.Int).value = klantId;  
                  cmd.Parameters.Add("@param2", SqlDbType.Varchar, 50).value = klantNaam;
                  cmd.Parameters.Add("@param3", SqlDbType.Varchar, 50).value = klantVoornaam;
                  cmd.CommandType = CommandType.Text;
                  cmd.ExecuteNonQuery(); 
            }
 }

Answer 2

你可以使用隐式转换 AddWithValue

cmd.Parameters.AddWithValue("@param1", klantId);
cmd.Parameters.AddWithValue("@param2", klantNaam);
cmd.Parameters.AddWithValue("@param3", klantVoornaam);

示例代码,

using (SqlConnection conn = new SqlConnection("connectionString")) 
{
    using (SqlCommand cmd = new SqlCommand()) 
    { 
        cmd.Connection = conn;
        cmd.CommandType = CommandType.Text;
        cmd.CommandText = @"INSERT INTO klant(klant_id,naam,voornaam) 
                            VALUES(@param1,@param2,@param3)";  

        cmd.Parameters.AddWithValue("@param1", klantId);  
        cmd.Parameters.AddWithValue("@param2", klantNaam);  
        cmd.Parameters.AddWithValue("@param3", klantVoornaam);  

        try
        {
            conn.Open();
            cmd.ExecuteNonQuery(); 
        }
        catch(SqlException e)
        {
            MessgeBox.Show(e.Message.ToString(), "Error Message");
        }

    } 
}