显示8年前的datepicker并在ios中锁定ui datepicker

Question

在我的项目中,我需要显示日期选择器18,我需要锁定80年后,所以如何在datepicker中显示这些日期可以任何人帮我在这里找到这里添加代码我的代码我打印在日志但我需要在我的日期选择器上显示,以便我如何显示

NSCalendar * gregorian = [[NSCalendar alloc] initWithCalendarIdentifier: NSGregorianCalendar];
NSDate * currentDate = [NSDate date];
NSDateComponents * comps = [[NSDateComponents alloc] init];
[comps setYear: -18];
NSDate * minDate = [gregorian dateByAddingComponents: comps toDate: currentDate options: 0];
[comps setYear: -100];
NSDate * maxDate = [gregorian dateByAddingComponents: comps toDate: currentDate options: 0];
[comps release];

self.datePickerView.minimumDate = minDate;
self.datePickerView.maximumDate = maxDate;

NSLog(@"minDate   %@", minDate);
NSLog(@"maxDate%@", maxDate);

Answer 1

首先,最短的日期必须是100年的回溯日期,最长的日期必须是18年的回溯日期,然后将pickerView的日期设置为日期范围之间的日期,以便最终的代码看起来像

NSCalendar * gregorian = [[NSCalendar alloc] initWithCalendarIdentifier: NSGregorianCalendar];
NSDate * currentDate = [NSDate date];
NSDateComponents * comps = [[NSDateComponents alloc] init];
[comps setYear: -18];
NSDate * maxDate = [gregorian dateByAddingComponents: comps toDate: currentDate options: 0];
[comps setYear: -100];
NSDate * minDate = [gregorian dateByAddingComponents: comps toDate: currentDate options: 0];
[comps release];

self.datePickerView.minimumDate = minDate;
self.datePickerView.maximumDate = maxDate;
self.datePickerView.date = minDate;

希望这对你有所帮助.