没有要聚合的数字类型 - 改变groupby()行为?

and*_*s-h 36 python pandas

我有一些组合代码的问题,我很确定曾经运行过(在较旧的pandas版本上).在0.9,我得到没有数字类型来聚合错误.有任何想法吗?

In [31]: data
Out[31]: 
<class 'pandas.core.frame.DataFrame'>
DatetimeIndex: 2557 entries, 2004-01-01 00:00:00 to 2010-12-31 00:00:00
Freq: <1 DateOffset>
Columns: 360 entries, -89.75 to 89.75
dtypes: object(360)

In [32]: latedges = linspace(-90., 90., 73)

In [33]: lats_new = linspace(-87.5, 87.5, 72)

In [34]: def _get_gridbox_label(x, bins, labels):
   ....:             return labels[searchsorted(bins, x) - 1]
   ....: 

In [35]: lat_bucket = lambda x: _get_gridbox_label(x, latedges, lats_new)

In [36]: data.T.groupby(lat_bucket).mean()
---------------------------------------------------------------------------
DataError                                 Traceback (most recent call last)
<ipython-input-36-ed9c538ac526> in <module>()
----> 1 data.T.groupby(lat_bucket).mean()

/usr/lib/python2.7/site-packages/pandas/core/groupby.py in mean(self)
    295         """
    296         try:
--> 297             return self._cython_agg_general('mean')
    298         except DataError:
    299             raise

/usr/lib/python2.7/site-packages/pandas/core/groupby.py in _cython_agg_general(self, how, numeric_only)
   1415 
   1416     def _cython_agg_general(self, how, numeric_only=True):
-> 1417         new_blocks = self._cython_agg_blocks(how, numeric_only=numeric_only)
   1418         return self._wrap_agged_blocks(new_blocks)
   1419 

/usr/lib/python2.7/site-packages/pandas/core/groupby.py in _cython_agg_blocks(self, how, numeric_only)
   1455 
   1456         if len(new_blocks) == 0:
-> 1457             raise DataError('No numeric types to aggregate')
   1458 
   1459         return new_blocks

DataError: No numeric types to aggregate
Run Code Online (Sandbox Code Playgroud)

Cha*_*She 43

你是如何生成数据的?

看看输出如何显示您的数据属于"对象"类型?groupby操作专门检查每列是否是数字dtype.

In [31]: data
Out[31]: 
<class 'pandas.core.frame.DataFrame'>
DatetimeIndex: 2557 entries, 2004-01-01 00:00:00 to 2010-12-31 00:00:00
Freq: <1 DateOffset>
Columns: 360 entries, -89.75 to 89.75
dtypes: object(360)
Run Code Online (Sandbox Code Playgroud)

看↑


您是否先初始化一个空的DataFrame然后填充它?如果是这样的原因可能就是为什么它随着新版本的变化而变化,之前0.9空的DataFrames被初始化为float类型,但现在它们是对象类型.如果是这样,您可以将初始化更改为DataFrame(dtype=float).

你也可以打电话 frame.astype(float)

  • 奇怪,那么如何对包含字符串的字段进行分组呢?这似乎更适合标量分组,而不是基于列中的值。 (2认同)

小智 8

我通过以下方式完成了这项工作:

data_frame.groupby(COL1).COL2.apply(np.mean).reset_index()
Run Code Online (Sandbox Code Playgroud)


Bla*_*ook 7

生成由时间戳和数据组成的数据帧时出现此错误:

df = pd.DataFrame({'data':value}, index=pd.DatetimeIndex(timestamp))
Run Code Online (Sandbox Code Playgroud)

添加建议的解决方案对我有用:

df = pd.DataFrame({'data':value}, index=pd.DatetimeIndex(timestamp), dtype=float))
Run Code Online (Sandbox Code Playgroud)

谢谢张她!

例:

                     data
2005-01-01 00:10:00  7.53
2005-01-01 00:20:00  7.54
2005-01-01 00:30:00  7.62
2005-01-01 00:40:00  7.68
2005-01-01 00:50:00  7.81
2005-01-01 01:00:00  7.95
2005-01-01 01:10:00  7.96
2005-01-01 01:20:00  7.95
2005-01-01 01:30:00  7.98
2005-01-01 01:40:00  8.06
2005-01-01 01:50:00  8.04
2005-01-01 02:00:00  8.06
2005-01-01 02:10:00  8.12
2005-01-01 02:20:00  8.12
2005-01-01 02:30:00  8.25
2005-01-01 02:40:00  8.27
2005-01-01 02:50:00  8.17
2005-01-01 03:00:00  8.21
2005-01-01 03:10:00  8.29
2005-01-01 03:20:00  8.31
2005-01-01 03:30:00  8.25
2005-01-01 03:40:00  8.19
2005-01-01 03:50:00  8.17
2005-01-01 04:00:00  8.18
                     data
2005-01-01 00:00:00  7.636000
2005-01-01 01:00:00  7.990000
2005-01-01 02:00:00  8.165000
2005-01-01 03:00:00  8.236667
2005-01-01 04:00:00  8.180000
Run Code Online (Sandbox Code Playgroud)