hig*_*dth 1 ruby mysql time activerecord ruby-on-rails-3.1
我想在MySQL表中节省时间.但是,日期将恢复为2000-01-01.
1.9.2p320 :036 > vv = Visitor.new
=> #<Visitor id: nil, ip_address: nil, num_day_visits: nil, last_visit: nil>
1.9.2p320 :037 > vv.last_visit = Time.now; vv.ip_address = "3.3.3.3"
=> "3.3.3.3"
1.9.2p320 :038 > vv.num_day_visits = 1
=> 1
1.9.2p320 :039 > vv
=> #<Visitor id: nil, ip_address: "3.3.3.3", num_day_visits: 1, last_visit: "2012-10-11 01:31:04">
1.9.2p320 :040 > vv.save
SQL (0.2ms) BEGIN
SQL (0.7ms) INSERT INTO `visitors` (`ip_address`, `last_visit`, `num_day_visits`) VALUES (?, ?, ?) [["ip_address", "3.3.3.3"], ["last_visit", 2012-10-11 01:31:04 -0400], ["num_day_visits", 1]]
(0.5ms) COMMIT
=> true
1.9.2p320 :042 > vv
=> #<Visitor id: 1199, ip_address: "3.3.3.3", num_day_visits: 1, last_visit: "2012-10-11 01:31:04">
1.9.2p320 :043 > Visitor.find(:all,:conditions=>{:ip_address => "3.3.3.3"})
Visitor Load (1.4ms) SELECT `visitors`.* FROM `visitors` WHERE `visitors`.`ip_address` = '3.3.3.3'
=> [#<Visitor id: 1199, ip_address: "3.3.3.3", num_day_visits: 1, last_visit: "2000-01-01 05:31:04">]
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因此,当我检索记录时,日期是2000-01-01.
MySQL中的表:
mysql> describe visitors ;
+----------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+----------------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| ip_address | varchar(255) | NO | | NULL | |
| num_day_visits | int(11) | NO | | NULL | |
| last_visit | time | NO | | NULL | |
+----------------+--------------+------+-----+---------+----------------+
4 rows in set (0.00 sec)
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更新:我创建了一个玩具桌来玩转换时间到时间.这是发生的事情:
mysql> select * from example ;
+----+----------+
| id | mytime |
+----+----------+
| 1 | 11:13:00 |
+----+----------+
1 row in set (0.00 sec)
mysql> alter table example change mytime mytime datetime;
Query OK, 1 row affected, 1 warning (0.02 sec)
Records: 1 Duplicates: 0 Warnings: 1
mysql> select * from example ;
+----+---------------------+
| id | mytime |
+----+---------------------+
| 1 | 0000-00-00 00:00:00 |
+----+---------------------+
1 row in set (0.00 sec)
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这样就破坏了价值.我试图通过改变表格来回去,并使用一个新行.从头开始:
mysql> select * from example ;
+----+----------+
| id | mytime |
+----+----------+
| 2 | 11:13:00 |
+----+----------+
1 row in set (0.00 sec)
mysql> ALTER TABLE example CHANGE mytime mytime DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP();
ERROR 1067 (42000): Invalid default value for 'mytime'
mysql> ALTER TABLE example CHANGE mytime mytime DATETIME NOT NULL DEFAULT CURRENT_DATE();
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CURRENT_DATE()' at line 1
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显然,这很难.
这是因为您的last_visit列属于time而非datetime类型.最初我假设mysql只是01-01-2000用作内部表示时间字段的某种默认日期,但是看起来01-01-2000是rails而不是mysql.看看代表红宝石中没有日期的时间
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