Maë*_*son 1 c++ templates variadic-templates c++11
我试图弄清楚如何创建一个C++ 11模板函数,它将在两个约定之间转换函数调用:第一个是使用Variant(注意:变体是一个多态类型,它是子类IntVariable的基础, DoubleVariant等),第二个是C函数调用.
我们在编译时知道每条信息:参数count是参数的数量,参数/返回类型取决于'cfunc'变量类型.
// We will assume that the two following functions are defined with their correct
// specializations.
template < typename T >
Variant * convertToVariant( T t );
template < typename T >
T convertFromVariant( Variant * variant );
// The following function is incomplete, the question is how to convert the
// variant parameters into a C function call ?
template < typename Return, typename... Arguments >
Variant * wrapCFunction< Return cfunc( Args... ) >(int argc, Variant ** argv) {
// Here comes the magic call of cfunc, something like :
if ( argc != mpl::count< Args... >::value )
throw std::runtime_error( "bad argument count" );
return cfunc( convertFromVariant< Args... >( argv[ X ] )... );
}
// Example use case :
int foo( int a, int b );
int main(void) {
int argc = 2;
Variant * argv[2] = { new IntVariant( 5 ), new IntVariant( 6 ) };
Variant * res = wrapCFunction< foo >( argc, argv );
IntVariant * intRes = dynamic_cast< IntVariant >( res );
return intRes ? intRes->value : -1;
}
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使用索引技巧,这很容易:
template<unsigned...> struct indices{};
template<unsigned N, unsigned... Is>
struct indices_gen : indices_gen<N-1, N-1, Is...>{};
template<unsigned... Is>
struct indices_gen<0, Is...> : indices<Is...>{};
// assuming the parameters were actually like this
template<typename Return, typename... Args, unsigned... Is>
Variant* wrapCFunction(Return (*cfunc)(Args...), int argc, Variant** argv, indices<Is...>) {
return cfunc(convertFromVariant<Args>(argv[Is])...);
}
template<typename Return, typename... Args>
Variant* wrapCFunction(Return (*cfunc)(Args...), int argc, Variant** argv) {
if (argc != sizeof...(Args))
throw std::runtime_error("bad argument count");
return wrapCFunction(cfunc, argc, argv, indices_gen<sizeof...(Args)>());
}
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请注意代码中的一些更改.首先,sizeof...(Args)产生包中的参数数量.其次,我修改了函数的签名cfunc作为实际参数传递.
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