在C中是否有一个函数返回这样的变量的最大值(我将在下面的例子中命名函数"maxvalue")?
int a;
printf("%d", maxvalue(a)); // 32767
unsigned int b;
printf("%d", maxvalue(b)); // 65535
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所以基本上函数返回的值就像INT_MAX变量是有符号的INT,UINT_MAX是无符号的int等.
这种功能不是由C标准库定义的.您可以尝试定义计算它的宏:
#define MAX_VALUE(a) (((unsigned long long)1 << (sizeof(a) * CHAR_BIT)) - 1)
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使用时,请注意将其分配给足够大的类型.例如:
#include <stdlib.h>
#include <stdio.h>
#include <limits.h>
#define IS_TYPE_SIGNED(a) ((a-1) < 0)
#define MAX_VALUE_UNSIGNED(a) (((unsigned long long)1 << \
(sizeof(a) * CHAR_BIT)) - 1)
#define MAX_VALUE_SIGNED(a) (MAX_VALUE_UNSIGNED(a) >> 1)
#define MAX_VALUE(a) (IS_TYPE_SIGNED(a) ? \
MAX_VALUE_SIGNED(a) : MAX_VALUE_UNSIGNED(a))
int main(void)
{
unsigned int i = 0;
signed int j = 0;
printf("%llu\n", MAX_VALUE(i));
printf("%llu\n", MAX_VALUE(j));
return EXIT_SUCCESS;
}
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打印出:
4294967295
2147483647
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您可以使用C11类型通用表达式轻松完成:
#define maxvalue(type) _Generic(type, int: INT_MAX, \
unsigned int: UINT_MAX)
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它不是一个功能,但我认为它可以满足您的需求.这是一个简单的示例程序:
#include <stdio.h>
#include <limits.h>
#define maxvalue(type) _Generic(type, int: INT_MAX, \
unsigned int: UINT_MAX)
int main(void)
{
int i;
unsigned int ui;
printf("%u\n", maxvalue(i));
printf("%u\n", maxvalue(ui));
return 0;
}
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它的输出:
$ clang -Wall -Werror -Wextra -pedantic -std=c11 example.c -o example
$ ./example
2147483647
4294967295
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我的答案比你的大,因为我的系统有32位整数.您似乎有一台16位计算机.
以下是我的库中适用于类型而不是变量的宏:
/* min and max integer values. T is a signed or unsigned integer type. */
/* Returns 1 if T is signed, else 0. */
#define INTTYPE_SIGNED(T) ((T)-1 < (T)0)
/*
* Returns (T)(maximum value of a T).
*
* Pains are taken (perhaps unnecessarily) to avoid integer overflow
* with signed types.
*/
#define INTTYPE_MAX(T) \
(((T)1 << (CHAR_BIT*sizeof(T)-INTTYPE_SIGNED(T)-1)) - 1 + \
((T)1 << (CHAR_BIT*sizeof(T)-INTTYPE_SIGNED(T)-1)))
/*
* Returns (T)(minimum value of a T).
* Pains are taken (perhaps unnecessarily) to avoid integer overflow
* with signed types.
* assert: twos complement architecture
*/
#define INTTYPE_MIN(T) ((T)(-INTTYPE_MAX(T)-1))
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编辑:将这些内容适应问题:
/* min and max integer values. V is a signed or unsigned integer value. */
/* Returns 1 if V has signed type, else 0. */
#define INT_VALUE_SIGNED(V) ((V)-(V)-1 < 0)
/*
* Returns maximum value for V's type.
*
* Pains are taken (perhaps unnecessarily) to avoid integer overflow
* with signed types.
*/
#define INT_VALUE_MAX(V) \
(((V)-(V)+1 << (CHAR_BIT*sizeof(V)-INT_VALUE_SIGNED(V)-1)) - 1 + \
((V)-(V)+1 << (CHAR_BIT*sizeof(V)-INT_VALUE_SIGNED(V)-1)))
/*
* Returns minimum value for V's type.
* Pains are taken (perhaps unnecessarily) to avoid integer overflow
* with signed types.
* assert: twos complement architecture
*/
#define INT_VALUE_MIN(V) (-INT_VALUE_MAX(V)-1)
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事后思考:如果 V 是变量或包含变量的表达式,且尚未赋值,则这些调用 UB ...这就是所提出的问题中的情况。它们可能适用于许多实现,但 C 标准并不保证这一点,并且它们肯定会在使用陷阱值初始化未初始化变量的实现上失败。