使用FOR XML的SQL Server EXPLICIT模式

Question

我正在使用SQL Server 2008,我正在尝试使用EXPLICIT模式生成自定义xml FOR XML.

我有以下查询的一对多关系

select  
    p.personid, p.firstname, a.P_City 
from 
    tblPeople p with (nolock) 
left outer join 
    tblAddresses a with (nolock) on p.personid = a.personid 
where 
    p.personid = 120773

我希望人作为父母和地址作为孩子可能是多个因为人们要解决有一对多的关系.

我写了以下查询

 select 1 as TAG,
        null as parent, 
        p.personid as [person!1!personid],
        p.FirstName as [person!1!firstname],

        null as [addr!2!] 
        from tblPeople p with (nolock) where p.PersonID in (120773,117396)

        union all 

select 2,1, 
        p.PersonID, p.FirstName, a.P_City from tblAddresses a with(nolock), tblPeople p 
        where p.PersonID=a.PersonID and p.PersonID in (120773,117396)

        for xml explicit

输出如下,与人嵌套的xml破解我的代码确实存在一些问题.

<person personid="117396" firstname="David"/>
    <person personid="120773" firstname="Doyle">
        <addr>Mount Rainier</addr>
        <addr>Annapolis</addr>
</person>

有人可以帮帮我!!!

Answer 1

我会建议放弃FOR XML EXPLICIT并使用FOR XML PATH/ROOT.

在此处使用此查询:

select  
    p.personid AS "@ID", 
    p.firstname, p.LastName,
    (
        SELECT AddressID AS "@ID", City
        FROM dbo.Address a 
        WHERE a.PersonID = p.PersonID
        FOR XML PATH('addr'), TYPE
    ) AS Addresses
from 
    Person p with (nolock) 
where 
    p.personid = 120773
FOR XML PATH('Person'), ROOT('People')

你会得到这个输出XML:

<People>
  <Person ID="120773">
    <firstname>John</firstname>
    <LastName>Doyle</LastName>
    <Addresses>
      <addr ID="1">
        <City>Annapolis</City>
      </addr>
      <addr ID="2">
        <City>Mount Rainier</City>
      </addr>
    </Addresses>
  </Person>
</People>

必要时调整它.阅读有关FOR XML PATHMSDN的更多详细信息.