dan*_*ess 11 stored-procedures sql-server-2008 database-schema
任何人都可以建议在数据库中列出所有存储过程及其模式名称吗?谢谢!
Aar*_*and 29
SELECT [schema] = OBJECT_SCHEMA_NAME([object_id]),
name
FROM sys.procedures;
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要么
SELECT [schema] = SCHEMA_NAME([schema_id]),
name
FROM sys.procedures;
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对于特定的数据库,您可以先将该上下文更改为该数据库,或稍微更改Marc的查询(在这种情况下我的查询不好,因为它们依赖于上下文相关的函数):
SELECT
SchemaName = s.name,
ProcedureName = pr.name
FROM
databasename.sys.procedures pr
INNER JOIN
databasename.sys.schemas s ON pr.schema_id = s.schema_id;
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如果要对所有数据库执行此操作:
DECLARE @sql NVARCHAR(MAX) = N'';
SELECT @sql += N'
UNION ALL SELECT db = N''' + name + ''',
s.name COLLATE Latin1_General_CI_AI,
o.name COLLATE Latin1_General_CI_AI
FROM ' + QUOTENAME(name) + '.sys.procedures AS o
INNER JOIN ' + QUOTENAME(name) + '.sys.schemas AS s
ON o.[schema_id] = s.[schema_id]'
FROM sys.databases
-- WHERE ... -- probably don't need system databases at least
SELECT @sql = STUFF(@sql, 1, 18, '')
-- you may have to adjust ^^ 18 due to copy/paste, cr/lf, tabs etc
+ ' ORDER BY by db, s.name, o.name';
EXEC sp_executesql @sql;
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如果您拥有具有不同排序规则的数据库,则必须使用collate子句.
mar*_*c_s 12
试试这个:
SELECT
SchemaName = s.name,
ProcedureName = pr.name
FROM
sys.procedures pr
INNER JOIN
sys.schemas s ON pr.schema_id = s.schema_id
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这应该列出所有存储过程及其架构名称作为结果集.
两个视图 - sys.procedures以及sys.schemas- 还有更多属性 - 如果需要,请检查它们,将它们包含在查询中.
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