无法在Visual Studio 2012中调试单元测试项目

Question

我找不到类似的帖子,所以我希望这不是重复的.

我有一个ac #class库,我正在尝试在Visual Studio 2012中运行单元测试.我在我的解决方案中添加了一个新的单元测试项目,并在那里添加了我的主项目作为参考.我已将我的单元测试项目设置为启动项目.当我尝试调试时,收到错误消息

无法直接启动具有类库的输出类型的项目.

要调试此项目,请将可执行项目添加到此解决方案,该项目引用库项目.将可执行项目设置为启动项目.

根据msdn的演练,我应该在调试时运行测试.有什么想法吗？这是我的单元测试代码:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

using Microsoft.VisualStudio.TestTools.UnitTesting;
using Common;
using Messages;

namespace MessageUnitTests
{
    [TestClass]
    class RegistrationTester
    {
        [TestMethod]
        public void RegistrationRequest_TestConstructorsAndFactories()
        {
            RegistrationRequest rr1 = new RegistrationRequest("myhandle");
            Assert.AreEqual("myhandle", rr1.Handle);

            rr1 = new RegistrationRequest("longHandle-ABCDEFGHIJKLMNOPQRSTUVWXYZ-0123456789'|;:',.=-_+!@#$%^&*()");
            Assert.AreEqual("longHandle-ABCDEFGHIJKLMNOPQRSTUVWXYZ-0123456789'|;:',.=-_+!@#$%^&*()", rr1.Handle);

            rr1 = new RegistrationRequest("");
            Assert.AreEqual("", rr1.Handle);

            rr1 = new RegistrationRequest(null);
            Assert.AreEqual(null, rr1.Handle);

            rr1 = new RegistrationRequest("myhandle");
            ByteList bytes = new ByteList();
            rr1.Encode(bytes);

            RegistrationRequest rr2 = RegistrationRequest.Create(bytes);
            Assert.IsNotNull(rr2);
            Assert.AreEqual(rr1.IsARequest, rr2.IsARequest);
            Assert.AreEqual(rr1.MessageNr.ProcessId, rr2.MessageNr.ProcessId);
            Assert.AreEqual(rr1.MessageNr.SeqNumber, rr2.MessageNr.SeqNumber);
            Assert.AreEqual(rr1.ConversationId.ProcessId, rr2.ConversationId.ProcessId);
            Assert.AreEqual(rr1.ConversationId.SeqNumber, rr2.ConversationId.SeqNumber);
            Assert.AreEqual(rr1.RequestType, rr2.RequestType);
            Assert.AreEqual(rr1.SessionId, rr1.SessionId);
            Assert.AreEqual(rr1.Handle, rr2.Handle);
        }

        //[TestMethod]
        //public void RegistrationRequest_EncodingDecoding()
        //{
        //    Message m1 = new RegistrationRequest("myhandle");
        //    m1.MessageNr = MessageNumber.Create(10, 14);
        //    m1.ConversationId = MessageNumber.Create(10, 12);
        //    ByteList bytes = new ByteList
        //}
    }
}

Answer 1

您将要以不同的方式调试它: