Joh*_*iss 5 haskell protocol-buffers conduit
目标是使用具有以下类型签名的管道
protobufConduit :: MonadResource m => (ByteString -> a) -> Conduit ByteString m a
Run Code Online (Sandbox Code Playgroud)
管道应重复解析ByteString -> a通过TCP/IP(使用network-conduit包)接收的协议缓冲区(使用该功能).
有线消息格式是
{length (32 bits big endian)}{protobuf 1}{length}{protobuf 2}...
Run Code Online (Sandbox Code Playgroud)
(花括号不是协议的一方,仅用于分隔实体).
第一个想法是使用sequenceSink重复应用Sink能够解析一个ProtoBuf:
[...]
import qualified Data.Binary as B
import qualified Data.Conduit.Binary as CB
import qualified Data.Conduit.Util as CU
protobufConduit :: MonadResource m => (ByteString -> a) -> Conduit ByteString m a
protobufConduit protobufDecode =
CU.sequenceSink () $ \() ->
do lenBytes <- CB.take 4 -- read protobuf length
let len :: Word32
len = B.decode lengthBytes -- decode ProtoBuf length
intLen = fromIntegral len
protobufBytes <- CB.take intLen -- read the ProtoBuf bytes
return $ CU.Emit () [ protobufDecode protobufBytes ] -- emit decoded ProtoBuf
Run Code Online (Sandbox Code Playgroud)
它不起作用(仅适用于第一个协议缓冲区),因为似乎已经从源中读取了许多"剩余"字节,但是没有通过CB.take丢弃而消耗掉这些字节.
我发现无法将"其余部分推回源头".
我的概念完全错了吗?
PS:即使我在这里使用协议缓冲区,问题也与协议缓冲区无关.为了调试这个问题,我总是使用{length}{UTF8 encoded string}{length}{UTF8 encoded string}...和上面一个类似的导管(utf8StringConduit :: MonadResource m => Conduit ByteString m Text).
我只是尝试用()剩余的字节替换状态(上面的示例中没有状态),并CB.take通过调用首先消耗已经读取的字节(来自状态)的函数来替换调用,并且await仅在需要时调用(当状态为不够大).不幸的是,这也不起作用,因为只要Source没有剩余字节,sequenceSink就不会执行代码,但状态仍然包含剩余的字节:-(.
如果你应该对代码感兴趣(没有优化或非常好,但应该足以测试):
utf8StringConduit :: forall m. MonadResource m => Conduit ByteString m Text
utf8StringConduit =
CU.sequenceSink [] $ \st ->
do (lengthBytes, st') <- takeWithState BS.empty st 4
let len :: Word32
len = B.decode $ BSL.fromChunks [lengthBytes]
intLength = fromIntegral len
(textBytes, st'') <- takeWithState BS.empty st' intLength
return $ CU.Emit st'' [ TE.decodeUtf8 $ textBytes ]
takeWithState :: Monad m
=> ByteString
-> [ByteString]
-> Int
-> Pipe l ByteString o u m (ByteString, [ByteString])
takeWithState acc state 0 = return (acc, state)
takeWithState acc state neededLen =
let stateLenSum = foldl' (+) 0 $ map BS.length state
in if stateLenSum >= neededLen
then do let (firstChunk:state') = state
(neededChunk, pushBack) = BS.splitAt neededLen firstChunk
acc' = acc `BS.append` neededChunk
neededLen' = neededLen - BS.length neededChunk
state'' = if BS.null pushBack
then state'
else pushBack:state'
takeWithState acc' state'' neededLen'
else do aM <- await
case aM of
Just a -> takeWithState acc (state ++ [a]) neededLen
Nothing -> error "to be fixed later"
Run Code Online (Sandbox Code Playgroud)
对于协议缓冲区解析和序列化,我们使用messageWithLengthPutMand messageWithLengthGetM(见下文),但我假设它对长度使用 varint 编码,这不是您需要的。我可能会尝试通过将messageWithLengthGet/Put 替换为类似的内容来调整我们下面的实现
myMessageWithLengthGetM =
do size <- getWord32be
getMessageWithSize size
Run Code Online (Sandbox Code Playgroud)
但我不知道如何getMessageWithSize使用协议缓冲区包中的可用函数来实现。另一方面,您可以getByteString“重新解析”字节串。
关于管道:您是否尝试过在不使用 的情况下实现管道Data.Conduit.Util?就像是
protobufConduit protobufDecode = loop
where
loop =
do len <- liftM convertLen (CB.take 4)
bs <- CB.take len
yield (protobufDecode bs)
loop
Run Code Online (Sandbox Code Playgroud)
这是我们使用的代码:
pbufSerialize :: (ReflectDescriptor w, Wire w) => Conduit w IO ByteString
pbufSerialize = awaitForever f
where f pb = M.mapM_ yield $ BSL.toChunks $ runPut (messageWithLengthPutM pb)
pbufParse :: (ReflectDescriptor w, Wire w, Show w) => Conduit ByteString IO w
pbufParse = new
where
new = read (runGet messageWithLengthGetM . BSL.fromChunks . (:[]))
read parse =
do mbs <- await
case mbs of
Just bs -> checkResult (parse bs)
Nothing -> return ()
checkResult result =
case result of
Failed _ errmsg -> fail errmsg
Partial cont -> read (cont . Just . BSL.fromChunks . (:[]))
Finished rest _ msg ->
do yield msg
checkResult (runGet messageWithLengthGetM rest)
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
613 次 |
| 最近记录: |