正则表达式 - 从给定字符串中提取子字符串

Question

我这里有一个字符串This is a string: AAA123456789.

所以这里的想法是AAA123456789使用正则表达式提取字符串.

我将它与X-Path结合在一起.

注意:如果有帖子,请引导我.

我认为,正确的,我应该substring(myNode, [^AAA\d+{9}]),

我不太确定正则表达式部分.

我们的想法是在遇到"AAA"时提取字符串,只有数字,但只有9个后续数字.

Answer 1

纯XPath解决方案:

substring-after('This is a string: AAA123456789', ': ')

产生:

AAA123456789

XPath 2.0解决方案:

tokenize('This is a string: AAA123456789 but not an double',
              ' '
              )[starts-with(., 'AAA')]

要么:

tokenize('This is a string: AAA123456789 but not an double',
              ' '
              )[matches(., 'AAA\d+')]

要么:

replace('This is a string: AAA123456789 but not an double',
              '^.*(A+\d+).*$',
              '$1'
              )