纯CSS替换OL> LI元素中的句点

Sup*_*tar 3 html css styles html-lists

据我所知,无论list-style-type你设置什么属性,分隔列表的数字或字母后面都会跟一个句点(.).有没有办法将其更改为,例如,右括号()),甚至完全删除它?

概念


这是不正确的CSS显示我想要做的事情:

<HTML>
<HEAD>
<STYLE>
OL{
  list-style-type:decimal;
  list-style-punctuation: ')';
}
OL.onlyNumbers{
  list-style-punctuation: none;
}
</STYLE>
</HEAD>
<BODY>
<OL>
  <LI>Won</LI>
  <LI>Too</LI>
  <LI>Tree</LI>
  <LI>Fore</LI>
  <LI VALUE=100>Won Hun Dread</LI>
</OL>
<OL CLASS=onlyNumbers>
  <LI>Won</LI>
  <LI>Too</LI>
  <LI>Tree</LI>
  <LI>Fore</LI>
  <LI VALUE=100>Won Hun Dread</LI>
</OL>
</BODY>
</HTML>
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以下是我想在浏览器中看到的内容:

  1) Won
  2) Too
  3) Tree
  4) Fore
100) Won Hun Dread

  1 Won
  2 Too
  3 Tree
  4 Fore
100 Won Hun Dread
Run Code Online (Sandbox Code Playgroud)

我不希望任何与jQuery或JavaScript有关的事情.我希望它尽可能接近正确的HTML 5和CSS 3.

Gio*_*ona 8

您可以使用before伪元素和CSScounter功能.

body {
    counter-reset:withBrackets;
    counter-reset:onlyNumbers;
}    
ol {
    list-style:none;
}
ol:not(.onlyNumbers) li {
    counter-increment:withBrackets;
}
ol:not(.onlyNumbers) li:before {
    content:counter(withBrackets) ") ";
}
ol.onlyNumbers li {
    counter-increment:onlyNumbers;
}
ol.onlyNumbers li:before {
    content:counter(onlyNumbers) " ";
}
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查看工作演示

  • @Supuhstar,是的,这可以用罗马人完成.请参阅http://coreyjmahler.com/html-pages/zlist-styles.html (2认同)