您尝试执行不包含指定表达式'out_time'的查询作为ms访问中的聚合函数

Question

我使用Ms访问作为我的数据库,我正在使用以下查询来获取时间:

select 
        in_time,
        out_time,
        datediff("n",b.in_time,c.out_time) as work_time,
        log_date,
        emp_id 
from 
    (select 
        LogTime as in_time,
        SrNo,
        LogID as emp_id,
        LogDate as log_date 
    from LogTemp 
    where Type='IN' ) as b
left join
    (select 
        SrNo as out_id, 
        LogTime as out_time,
        LogID as out_emp_id,
        LogDate as out_log_date 
      from LogTemp 
     where Type = 'OUT'
     group by SrNo) as c
on (b.SrNo <> c.out_id
    and b.emp_id = c.out_emp_id
    and b.log_date = out_log_date ) 
where  
    c.out_id > b.SrNo and 
    [log_date] >= #8/20/2012# and 
    [log_date] <= #8/20/2012# and 
    emp_id = "8" 
group by b.SrNo; 

但是当我执行查询时,我得到以下错误:

"you tried to execute a query that does not include the specified expression 'out_time'
 as an aggregate function in ms access" error.

我犯错误的任何建议.

Answer 1

你有几个错误,如果你想做一个GROUP BY.首先检查MSDN的GROUP BY语法,建议和示例.

基本上,没有不断深入,如果你使用GROUP BY,在任何列SELECT条款不受聚集功能SUM,AVG等等,应该出现在GROUP BY条款.所以在你的情况下你应该添加:

LogTime as out_time,
LogID as out_emp_id,
LogDate as out_log_date

进入第二个子查询的GROUP BY.并添加

 in_time,
 out_time,
 datediff("n",b.in_time,c.out_time) as work_time,
 log_date,
 emp_id 

在最后的主要GROUP BY.

但是,正如已经在一条评论中指出的那样,也许你想做的是一个ORDER BY.那么应尽可能更换容易GROUP通过ORDER,它应该工作.只要确定你想要的是什么.