在Google Maps API v3中找到最短和最快路线的优雅方法?

Abs*_*act 12 google-maps google-maps-api-3

我正在制作出租车费用计算器.其中一项业务要求是,公司需要最短和最快的路线选择.我知道Google DirectionsService默认搜索最快的路线.我将request参数中的"avoidhighways"选项设置为true以获得最短路径,但我对结果不太满意.

任何人都有比这更好的解决方案?

Sol*_*tos 6

要获得从A到BI的最短路径,建议使用"alternatives = true"参数进行不同的查询,在avoid = toll,avoid = highways之间玩"avoid"参数,然后我会比较所有结果以选择最短的路线.

 directionsService = new google.maps.DirectionsService;
//avoiding tolls
            directionsService.route({
                origin: {
                    'placeId': originId
                },
                destination: {
                    'placeId': destinationId
                },
                provideRouteAlternatives: true,
                avoidTolls: true,
                travelMode: google.maps.TravelMode.DRIVING
            }, function(response, status) {
                if (status === google.maps.DirectionsStatus.OK) {
                    routesResponses.push(response);
                }
                else {
                    window.alert('Directions request failed due to ' + status);
                }
            });
            //avoiding highways
            directionsService.route({
                origin: {
                    'placeId': originId
                },
                destination: {
                    'placeId': destinationId
                },
                provideRouteAlternatives: true,
                avoidHighways: true,
                travelMode: google.maps.TravelMode.DRIVING
            }, function(response, status) {
                if (status === google.maps.DirectionsStatus.OK) {
                    routesResponses.push(response);
                }
                else {
                    window.alert('Directions request failed due to ' + status);
                }

                //Results analysis and drawing of routes
                var fastest = Number.MAX_VALUE,
                    shortest = Number.MAX_VALUE;

                routesResponses.forEach(function(res) {
                    res.routes.forEach(function(rou, index) {
                        console.log("distance of route " +index+": " , rou.legs[0].distance.value);
                        console.log("duration of route " +index+": " , rou.legs[0].duration.value);
                        if (rou.legs[0].distance.value < shortest) shortest = rou.legs[0].distance.value  ;
                        if (rou.legs[0].duration.value < fastest) fastest = rou.legs[0].duration.value  ;

                    })
                })
                console.log("shortest: ", shortest);
                console.log("fastest: ", fastest);
//painting the routes in green blue and red
                 routesResponses.forEach(function(res) {
                    res.routes.forEach(function(rou, index) {
                        new google.maps.DirectionsRenderer({
                            map:map,
                            directions:res,
                            routeIndex:index,
                            polylineOptions:{
                                strokeColor: rou.legs[0].duration.value == fastest? "red":rou.legs[0].distance.value == shortest?"darkgreen":"blue",
                                strokeOpacity: rou.legs[0].duration.value == fastest? 0.8:rou.legs[0].distance.value == shortest? 0.9: 0.5,
                                strokeWeight: rou.legs[0].duration.value == fastest? 9:rou.legs[0].distance.value == shortest? 8: 3,
                            }
                        })
                    })
                })   
            });
        }

    }
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Jam*_*ull 3

通过选项集,您将获得三个选项alternatives=true。然后,您可以搜索返回的路线中最短和最快的路线。