Jer*_*uff 5 php timeout try-catch simplexml
我有这个输出rss feed的脚本.我想要做的是让它尝试到达5秒顶部的rss网址,如果它不能,那么我希望它加载服务器上的备份xml文档.这就是我所拥有的,它不起作用:
<?php
include '../php/connect.php';
$metaData = mysql_query("SELECT * FROM `siteinfo`") or die("couln't find table :(");
$displayData = mysql_fetch_assoc($metaData);
$url = $displayData['status'];
$xml = file_get_contents($url);
stream_set_timeout($xml, 5);
if ($xml == FALSE) {
$xml = simplexml_load_file('backUpXml.xml');
foreach ($xml->channel->item as $item) {
echo '<a href="'.$item->guid.'" alt="'.$item->title.'" target="_blank">', substr($item->title, 0, 62), '...</a><br /><span>', substr($item->pubDate, 4, 18),'</span><br /><hr /><br />';
}
} else {
$xml = simplexml_load_file($url);
foreach ($xml->channel->item as $item) {
echo '<a href="'.$item->guid.'" alt="'.$item->title.'" target="_blank">', substr($item->title, 0, 62), '...</a><br /><span>', substr($item->pubDate, 4, 18),'</span><br /><hr /><br />';
}
}
?>
Run Code Online (Sandbox Code Playgroud)
我有一个超时错误,就是这样.任何见解都会很棒!
这就是我的工作:
<?php
include 'php/connect.php' ;
$metaData = mysql_query("SELECT * FROM `siteinfo`") or die("couln't find table :(");
$displayData = mysql_fetch_assoc($metaData);
$url = $displayData['status'];
$xml = file_get_contents($url);
if (!$xml) {
$xml = simplexml_load_file('content/backUpXml.xml');
foreach ($xml->channel->item as $item) {
echo '<a href="'.$item->guid.'" alt="'.$item->title.'" target="_blank">', substr($item->title, 0, 62), '...</a><br /><span>', substr($item->pubDate, 4, 18),'</span><br /><hr /><br />';
}
} else {
$myFile = "content/backUpXml.xml";
$fh = fopen($myFile, 'w') or die("can't open file");
$stringData = $xml;
fwrite($fh, $stringData);
fclose($fh);
$xml = simplexml_load_file($url);
foreach ($xml->channel->item as $item) {
echo '<a href="'.$item->guid.'" alt="'.$item->title.'" target="_blank">', substr($item->title, 0, 62), '...</a><br /><span>', substr($item->pubDate, 4, 18),'</span><br /><hr /><br />';
}
}
?>
Run Code Online (Sandbox Code Playgroud)