Cur*_*ous 25 python sorting pandas
如何根据最后一行的值对列进行排序?在下面的例子中,我的最终df将按以下顺序排列:'ddd''aaa''ppp''ffff'.
>>> df = DataFrame(np.random.randn(10, 4), columns=['ddd', 'fff', 'aaa', 'ppp'])
>>> df
ddd fff aaa ppp
0 -0.177438 0.102561 -1.318710 1.321252
1 0.980348 0.786721 0.374506 -1.411019
2 0.405112 0.514216 1.761983 -0.529482
3 1.659710 -1.017048 -0.737615 -0.388145
4 -0.472223 1.407655 -0.129119 -0.912974
5 1.221324 -0.656599 0.563152 -0.900710
6 -1.816420 -2.898094 -0.232047 -0.648904
7 2.793261 0.568760 -0.850100 0.654704
8 -2.180891 2.054178 -1.050897 -1.461458
9 -1.123756 1.245987 -0.239863 0.359759
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DSM*_*DSM 24
[更新以简化]
TL;博士:
In [29]: new_columns = df.columns[df.ix[df.last_valid_index()].argsort()]
In [30]: df[new_columns]
Out[30]:
aaa ppp fff ddd
0 0.328281 0.375458 1.188905 0.503059
1 0.305457 0.186163 0.077681 -0.543215
2 0.684265 0.681724 0.210636 -0.532685
3 -1.134292 1.832272 0.067946 0.250131
4 -0.834393 0.010211 0.649963 -0.551448
5 -1.032405 -0.749949 0.442398 1.274599
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一些解释如下.一,建立DataFrame:
In [24]: df = pd.DataFrame(np.random.randn(6, 4), columns=['ddd', 'fff', 'aaa', 'ppp'])
In [25]: df
Out[25]:
ddd fff aaa ppp
0 0.503059 1.188905 0.328281 0.375458
1 -0.543215 0.077681 0.305457 0.186163
2 -0.532685 0.210636 0.684265 0.681724
3 0.250131 0.067946 -1.134292 1.832272
4 -0.551448 0.649963 -0.834393 0.010211
5 1.274599 0.442398 -1.032405 -0.749949
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获取最后一行:
In [26]: last_row = df.ix[df.last_valid_index()]
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获取将对其进行排序的索引:
In [27]: last_row.argsort()
Out[27]:
ddd 2
fff 3
aaa 1
ppp 0
Name: 5, Dtype: int32
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用它来索引df:
In [28]: df[last_row.argsort()]
Out[28]:
aaa ppp fff ddd
0 0.328281 0.375458 1.188905 0.503059
1 0.305457 0.186163 0.077681 -0.543215
2 0.684265 0.681724 0.210636 -0.532685
3 -1.134292 1.832272 0.067946 0.250131
4 -0.834393 0.010211 0.649963 -0.551448
5 -1.032405 -0.749949 0.442398 1.274599
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利润!
小智 15
sort_values给定axis=1参数时,该方法直接执行此操作.
sorted_df = df.sort_values(df.last_valid_index(), axis=1)
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因此,不再需要将数据帧转置为按行排序.此外,该sort方法现已弃用.
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