该表包含城市及其分支/自动取款机的数据
CITY TYPE NAME
----------------------------------
agra atm X
agra branch X1
delhi atm X2
agra atm X3
agra atm X4
delhi branch X5
chennai branch X6
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期望的结果集是
CITY ATM BRANCH
------------------------------------
agra 3 1
delhi 1 1
chennai 0 1
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我们是否可以在一个选择语句中执行此操作.
您可以像聚合中的条件求和一样执行此操作:
select t.city,
sum(case when type = 'atm' then 1 else 0 end) as ATM,
sum(case when type = 'branch' then 1 else 0 end) as branch
from t
group by t.city
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