JQuery Dynatree - 按名称搜索节点

Question

我想在我的页面上开始使用Dynatree,但是我可能需要按名称搜索我的树.你知道怎么做吗？

Answer 1

我不仅需要匹配节点,还需要有这些节点的整个路径.我写了这个功能,它适用于我.

库的修改:

var clear = true;

DynaTreeNode.prototype.search = function(pattern){

    if(pattern.length < 1 && !clear){
        clear = true;
        this.visit(function(node){
            node.expand(true);
            node.li.hidden = false;
            node.expand(false);
        });
    } else if (pattern.length >= 1) {
        clear = false;
        this.visit(function(node){
            node.expand(true);
            node.li.hidden = false;
        });

        for (var i = 0; i < this.childList.length; i++){
            var hide = {hide: false};
            this.childList[i]._searchNode(pattern, hide);
        }
    } 
},

DynaTreeNode.prototype._searchNode = function(pattern, hide){

    if (this.childList){
        // parent node

        var hideNode = true;
        for(var i = 0; i < this.childList.length; i++){
            var hideChild = {hide: false};
            this.childList[i]._searchNode(pattern, hideChild);
            hideNode = hideNode && hideChild.hide;
        }
        if(hideNode && !this._isRightWithPattern(pattern)){
            this._hideNode();
            hide.hide = true;
        } else {
            hide.hide = false;
        }

    } else {
        // leaf
        if (!this._isRightWithPattern(pattern)){
            this._hideNode();
            hide.hide = true;
        } else {
            hide.hide = false;
        }
    }
},

DynaTreeNode.prototype._isRightWithPattern = function(pattern){
    if((this.data.title.toLowerCase()).indexOf(pattern.toLowerCase()) >= 0){
        return true;
    }
    return false;
},

DynaTreeNode.prototype._hideNode = function(){
    if(this.li) {
      this.li.hidden = true;
    }
}

使用:

$("tree").dynatree("getRoot").search(pattern);

Answer 2

目前没有搜索功能，但您可以使用类似的功能（未测试）

var match = null;
tree.visit(function(node){
    if(node.data.title === "foo"){
        match = node;
        return false; // stop traversal (if we are only interested in first match)
    }
});
alert("Found " + match);