Gam*_*der 5 java file-upload apache-commons-fileupload
在gwt Web应用程序中.我必须发送一个文件和一些附加的参数.
在ServerSide上
try {
ServletFileUpload upload = new ServletFileUpload();
FileItemIterator iterator = upload.getItemIterator(request);
while (iterator.hasNext()) {
FileItemStream item = iterator.next();
if (item.isFormField()) {
String fieldName=item.getFieldName();
String fieldValue = Streams.asString(item.openStream());
System.out.println(" chk " +fieldName +" = "+ fieldValue);
} else {
stream = item.openStream();
fileName = item.getName();
mimetype = item.getContentType();
int c;
while ((c = stream.read()) != -1) {
System.out.print((char) c);
}
}
}
}catch (Exception e) {
// TODO: handle exception
e.printStackTrace();
}
System.out.println("out of try");
ByteArrayOutputStream output = new ByteArrayOutputStream();
int nRead;
while ((nRead = stream.read(buffer, 0, buffer.length)) != -1) {
System.out.println("lenth111" +nRead);
output.write(buffer, 0, nRead);
}
System.out.println("lenth" +nRead);
output.flush();
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使用此代码,我可以读取流.并且还在控制台上"打印出来"也打印出来
最后,while ((nRead = stream.read(buffer, 0, buffer.length)) != -1)
我得到了一个警告
警告:/ UploadFileServlet:org.apache.commons.fileupload.FileItemStream $ ItemSkippedException.
如何解决这个问题呢.??
回答有点迟,但我遇到了同样的问题.
为什么会出现异常:ItemSkippedException的JavaDocs解释了一下:
如果在创建FileItemStream的迭代器上调用Iterator.hasNext()之后尝试从FileIream读取数据,则会抛出此异常(FileItemStream.openStream()返回).
您正在使用while循环外部的InputStream 流导致该问题,因为调用了另一个迭代,该迭代将关闭(跳过)您尝试读取的文件InputStream.
解决方案:在while循环中使用InputStream.如果在处理文件之前需要所有表单字段,请确保在客户端以正确的顺序设置它.首先是所有字段,最后是文件.例如,使用JavaScript FormData:
var fd = new window.FormData();
fd.append("param1", param1);
fd.append("param2", param2);
// file must be last parameter to append
fd.append("file", file);
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在服务器端:
FileItemIterator iter = upload.getItemIterator(request);
while (iter.hasNext()) {
FileItemStream item = iter.next();
InputStream stream = item.openStream();
// the order of items is given by client, first form-fields, last file stream
if (item.isFormField()) {
String name = item.getFieldName();
String value = Streams.asString(stream);
// here we get the param1 and param2
} else {
String filename = item.getName();
String mimetype = item.getContentType();
ByteArrayOutputStream output = new ByteArrayOutputStream();
int nRead;
while ((nRead = stream.read(buffer, 0, buffer.length)) != -1) {
System.out.println("lenth111" +nRead);
output.write(buffer, 0, nRead);
}
System.out.println("lenth" +nRead);
output.flush();
}
}
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