结合多个awk命令

Question

假设以下输入:

$ cat example
{many lines of text}

Col1 Col2  Col3
foo  bar   2 
bar  baz   3
baz  bar   8
bar  foo   0
foo  baz   9
baz  bar   3

{many more lines of text}

以下两个awk片段解析了我之后的数据:

cat example | awk -v 'RS=\n\n' '/^Col1 /' | awk '$2 == "bar" && $3 > 1 {print $1}'
foo
baz
baz

如何将两个片段组合成一个awk,例如

awk '
...
...
...
' example

Answer 1

你可以做:

awk '/^Col1 /,/^$/{ if( $2 == "bar" && $3 > 1 ) print $1}' example

Answer 2

这似乎有效.

gawk '/^$/{getline;if(/^Col1/){doit=1}else{doit=0;}} doit && $2=="bar" && $3>1 {print $1}' example

分成带有注释的可读块,这是:

/^$/ {                      # Look for a blank line
  getline;                  # Get the next line
  if (/^Col1/) {            # See if your column heads exist.
    doit=1                  # If they do, set a boolean to true
  } else {
    doit=0;                 # Otherwise, false.
  }
}

doit && $2=="bar" && $3>1 { # Check the boolean AND your conditions, then
  print $1                  # print.
}