更新表而不命名所有列

Question

我找到了一种方法,使用此模板使来自不同数据库的两个表相互匹配:

INSERT [DestDB].[dbo].[TABLE]
SELECT source.* FROM 
[SourceDB].[dbo].[TABLE] AS source
LEFT OUTER JOIN
[DestDB].[dbo].[TABLE] AS dest
ON 
source.[PKColumn] = dest.[PKColumn]
WHERE dest.[PKcolumn] IS NULL

UPDATE dest
SET 
 dest.[PK_COLUMN1] = source.[PK_COLUMN1]
,dest.[COLUMN2] = source.[COLUMN2]
,dest.[COLUMN3] = source.[COLUMN3]
,dest.[COLUMN4] = source.[COLUMN4]
,dest.[COLUMN5] = source.[COLUMN5]
,dest.[COLUMN6] = source.[COLUMN6]
,dest.[COLUMN7] = source.[COLUMN7]
,dest.[COLUMN8] = source.[COLUMN8]

FROM 
[SourceDB].[dbo].[TABLE] AS source
INNER JOIN 
[DestDB].[dbo].[TABLE] AS dest
ON source.[PK_Column1] = dest.[PK_Column1]

然而,我正在使用的一些表至少有200列,虽然可以通过复制+粘贴的功能来实现这一点,但我只需要知道是否有一种方法不会让我得到Carpel Tunnel Syndrome.

我正在使用Microsoft SQL Server 2005.

有什么建议？

Answer 1

我不认为您可以在不命名的情况下更新列,但您可以使用SQL和sys.columns视图为您编写脚本:

select ',dest.[' + name + '] = source.[' + name +']' 
from sys.columns 
WHERE object_id = OBJECT_ID(N'[dbo].[Widgets]')

- 输出 -

,dest.[WidgetId] = source.[WidgetId]
,dest.[WidgetName] = source.[WidgetName]
,dest.[CreatedDt] = source.[CreatedDt]
,dest.[WidgetValue] = source.[WidgetValue]
,dest.[ModifiedDt] = source.[ModifiedDt]

唯一的另一种方法是不更新,而是截断dest表并执行 SELECT INTO

SELECT * INTO DEST FROM SOURCE