PyQt 4 - 未定义全局名称"SIGNAL"

Question

我试图将按钮信号连接到我创建的可调用信号,但由于某种原因,此错误不断弹出.我已经检查过确保导入了QtCore ...我还缺少什么？

示例代码:

from PyQt4 import QtCore
from PyQt4 import QtGui
import sys

class guiFindFiles(QtGui.QWidget):
    def __init__(self, parent=None):
        QtGui.QWidget.__init__(self, parent)

        #Create window
        self.setFixedSize(400,180)
        self.setWindowTitle("Choose the files to use")

        #Create all layouts to be used by window
        self.windowLayout = QtGui.QVBoxLayout()
        self.fileLayout1 = QtGui.QHBoxLayout()
        self.fileLayout2 = QtGui.QHBoxLayout()
        self.fileLayout3 = QtGui.QHBoxLayout()

        #Create the prompt for user to load in the q script to use
        self.qFileTF = QtGui.QLineEdit("Choose the q script file to use")
        self.qFileButton = QtGui.QPushButton("Open")
        self.qFileButton.setFixedSize(100,27)
        self.fileLayout1.addWidget(self.qFileTF)
        self.fileLayout1.addWidget(self.qFileButton)

                    #Connect all the signals and slots
        self.connect(self.qFileButton, SIGNAL("pressed()"), self.loadFile)

        def loadFile():
            fileName = []

            selFile = QtGui.QFileDailog.getOpenFileName(self)
            print selFile

Answer 1

SIGNAL在里面QtCore,所以该行应该是:

self.connect(self.qFileButton, QtCore.SIGNAL("pressed()"), self.loadFile)

但你真的应该使用新的风格连接:

self.qFileButton.pressed.connect(self.loadFile)

而且,除非你的意思是区分click由press/release夫妇,你最好使用clicked信号:

self.qFileButton.clicked.connect(self.loadFile)