E_l*_*ner 4 c++ opencv pixel matrix background-image
我想计算背景图像中只有黑色和白色的白点数.我有这样的代码:
int count = 0;
for ( int j = 0; j < Image.rows; j ++ )
{
for ( int i = 0; i < Image.cols; i ++ )
{
if ( Image.at<int>(i,j) >= 150 )
{
count ++ ;
}
}
}
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出于某种原因,上面的代码不起作用,它只是停止反应.我检查了,"if(Image.at(i,j)> = 150)"这一行导致了问题.我的"图像"是"cv :: Mat",带有"CV_8UC3"类型.有人可以帮助我吗?谢谢.
eta*_*ion 11
除了我对Robin的回答的评论之外,您的错误是您尝试以int为单位访问CV_8UC3类型的图像.如果要检查灰度级别,请执行以下操作(请注意"unsigned char"而不是"int",如Robin的答案).
cv::Mat greyscale;
cv::cvtColor(image,grayscale,CV_RGB2GRAY);
// either, most elegant:
int count = cv::countNonZero(greyscale >= 150);
// or, copied from Robin's answer:
int count = 0;
for(int i = 0; i < greyscale.rows; ++i) {
const unsigned char* row = greyscale.ptr<unsigned char>(i);
for(int j = 0; j < greyscale.cols; j++) {
if (row[j] >= 150)
++count;
}
}
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我相信这更整洁:
Mat result;
threshold(Image,result,150,255,THRESH_BINARY);
int white_count = countNonZero(result);
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