逐行组合列表(Python)

Question

假设我有3个不同的列表

col1 = ['2006-03-28','2006-04-05','2006-04-06']
col2 = ['IBM', 'MSFT', 'IBM']
col3 = [1000, 1000, 500]

将这些列表组合在另一个列表中的最有效方法是什么,如下所示:

col = [('2006-03-28', 'IBM', 1000),
       ('2006-04-05', 'MSFT', 1000),
       ('2006-04-06', 'IBM', 500)]

Answer 1

>>> col1 = ['2006-03-28','2006-04-05','2006-04-06']
>>> col2 = ['IBM', 'MSFT', 'IBM']
>>> col3 = [1000, 1000, 500]
>>> zip(col1, col2, col3)
[('2006-03-28', 'IBM', 1000), ('2006-04-05', 'MSFT', 1000), ('2006-04-06', 'IBM', 500)]

如果您的列已经在一个列表中,您可以使用 zip(*cols)