获取函数,Python的关键字参数

Question

def thefunction(a=1,b=2,c=3):
    pass

print allkeywordsof(thefunction) #allkeywordsof doesnt exist

会给[a,b,c]

是否有像allkeywordsof这样的功能？

我不能改变里面的任何东西, thefunction

Answer 1

我想你正在寻找inspect.getargspec:

import inspect

def thefunction(a=1,b=2,c=3):
    pass

argspec = inspect.getargspec(thefunction)
print(argspec.args)

产量

['a', 'b', 'c']

如果你的函数包含位置和关键字参数,那么找到关键字参数的名称有点复杂,但不是太难:

def thefunction(pos1, pos2, a=1,b=2,c=3, *args, **kwargs):
    pass

argspec = inspect.getargspec(thefunction)

print(argspec)
# ArgSpec(args=['pos1', 'pos2', 'a', 'b', 'c'], varargs='args', keywords='kwargs', defaults=(1, 2, 3))

print(argspec.args)
# ['pos1', 'pos2', 'a', 'b', 'c']

print(argspec.args[-len(argspec.defaults):])
# ['a', 'b', 'c']

Answer 2

你想要这样的东西吗：

>>> def func(x,y,z,a=1,b=2,c=3):
    pass

>>> func.func_code.co_varnames[-len(func.func_defaults):]
('a', 'b', 'c')