SyntaxError:检索JSON对象时无效的标签

Question

SyntaxError:检索JSON对象时无效的标签

检索JSON对象时收到以下错误:

SyntaxError:Mozilla中的无效标签.
未捕获的SyntaxError:意外的令牌:在Chrome中

我的JSON对象是如下所示的格式:

{
   "userName" : "clevermeal835",
   "userRole" : "Participant",
   "userAccountStatus" : "Active"
}

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码:

<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<script src="Scripts/jquery-min.js"></script>
<script src="Scripts/jquery_validate.js"></script>
<script>
$(document).ready(function() {
    loadLatestTweet();  
});

function loadLatestTweet(){
var xhr = new XMLHttpRequest();
var uid = "clevermeal835";
var pwd = "Welcome_1";
var userType = "participant";
    var surl =      'http://localhost:8080/RESTlet_WS/MobiSignIn/{"userName":"'+uid+'","password":"'+pwd+ '","userType":"'+userType+'"}&callback=?';

    var jqxhr = $.getJSON(surl, function() {
        alert("success");
    }).success(function() { alert("second success");   }).error(function() { alert("error"); }).complete(function() { alert("complete"); });
    jqxhr.complete(function(){ alert("second complete"); });
 }
 </script>
</head>
<body>
<input id="jsonpbtn2" type="submit" value="button" />
</body>
</html>

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Answer 1

Jig*_*Raj 3

你可以使代码看起来像这样

var params = { "Username": UserNameValue,"Password": PassValue};


        $.ajax({
            type: "POST",
            url: "http://localhost:8080/RESTlet_WS/MobiSignIn/",
            contentType: 'application/json',

            data: JSON.stringify(params),
            dataType: 'json',
            async: false,
            cache: false,
            success: function (response) {


            },
            error: function (ErrorResponse) {


            }

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