kal*_*alz 2 parsing android http-request
我正在使用Android Web服务器.当我在模拟器浏览器上访问localhost:8080时,它会提供带有密码字段的页面/表单.在成功验证密码后,我想将用户重定向到成功/失败页面.什么是读取传入的http post请求并解析密码字段以进行验证的最佳方法?正确方向的任何指针都是非常感激.我有一个提交表单的URL的处理程序.处理程序的代码是:
import java.io.IOException;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import org.apache.http.HttpEntity;
import org.apache.http.HttpException;
import org.apache.http.HttpRequest;
import org.apache.http.HttpResponse;
import org.apache.http.entity.ContentProducer;
import org.apache.http.entity.EntityTemplate;
import org.apache.http.protocol.HttpContext;
import org.apache.http.protocol.HttpRequestHandler;
import android.content.Context;
public class LoginHandler implements HttpRequestHandler {
private Context context = null;
public LoginHandler(Context context) {
this.context = context;
}
@Override
public void handle(final HttpRequest request, HttpResponse response,
HttpContext httpcontext) throws HttpException, IOException {
HttpEntity entity = new EntityTemplate(new ContentProducer() {
public void writeTo(final OutputStream outstream) throws IOException {
String resp = null;
OutputStreamWriter writer = new OutputStreamWriter(outstream, "UTF-8");
if(validatePassword()==true){
resp ="<html><head></head><body><h1>Home<h1><p>Success.</p></body></html>";
}
else{resp="<html><head></head><body><h1>Home<h1><p>Login Failed.</p></body></html>";}
writer.write(resp);
writer.flush();
}
});
response.setHeader("Content-Type", "text/html");
response.setEntity(entity);
}
boolean validatePassword(){
boolean pass=false;
//parse request body here and check for the password if true return true/else false
return pass;
}
}
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环顾四周后,我找到了解决方案.在handle方法中添加以下内容可以解决问题.感谢原始海报.http://www.androiddevblog.net/android/a-bare-minimum-web-server-for-android-platform
if (request instanceof HttpEntityEnclosingRequest) {
HttpEntity entity = ((HttpEntityEnclosingRequest) request).getEntity();
if (entity != null) {
Log.v("RequestBody", EntityUtils.toString(entity, "UTF-8"));
entity.consumeContent();
}
}
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