Google Maps API v3中的OVER_QUERY_LIMIT:如何暂停/延迟Javascript以减慢速度？

Question

Google Maps API v3中的OVER_QUERY_LIMIT:如何暂停/延迟Javascript以减慢速度？

use*_*571 40 javascript google-maps-api-3

我正在讨论在这些论坛中讨论的问题,但是没有一个建议似乎对我有用,所以我正在寻找一些完整的javascript,当保存为html文件时有效.

问题是当我尝试使用Javascript调用的V3 API在Google Map上对11个位置进行地理编码时,我一直遇到OVER_QUERY_LIMIT错误.我知道你可以调用地址解码器的速率是有限的(以及总音量的每日限制),所以我需要在数组中的每个结果之间引入一个暂停.

任何帮助非常感谢.

这是我的代码:

<script type="text/javascript" src="http://maps.google.com/maps/api/js?sensor=false"></script>
<script type="text/javascript">
var geocoder;
var map;
var wait = false;


  function initialize() {
geocoder = new google.maps.Geocoder();
var latlng = new google.maps.LatLng(51.32, 0.5);



var myOptions = {
  zoom: 8,
  center: latlng,
  mapTypeId: google.maps.MapTypeId.ROADMAP
}
map = new google.maps.Map(document.getElementById("map_canvas"), myOptions);
codeAddress('KT16 8LA' + ', UK');
codeAddress('LS8 2LQ' + ', UK');
codeAddress('NE13 8AF' + ', UK');
codeAddress('KT12 2BE' + ', UK');
codeAddress('W1W 8AN' + ', UK');
codeAddress('EC3N 2LS' + ', UK');
codeAddress('BS9 3BH' + ', UK');
codeAddress('KA10 6LZ' + ', UK');
codeAddress('EC1V 9BW' + ', UK');
codeAddress('WD18 8YN' + ', UK');
codeAddress('HA3 6DQ' + ', UK');
codeAddress('W1U 3PL' + ', UK');
codeAddress('W1T 7QL' + ', UK');
codeAddress('W1S 1TD' + ', UK');
codeAddress('SW1X 8NX' + ', UK');
codeAddress('LE2 8ET' + ', UK');
codeAddress('BA3 4BH' + ', UK');
codeAddress('AL3 8JP' + ', UK');
codeAddress('DE55 4QJ' + ', UK');
codeAddress('W6 0QT' + ', UK');
codeAddress('LA1 1PP' + ', UK');
codeAddress('SW16 4DH' + ', UK');
codeAddress('WC2N 6DF' + ', UK');
codeAddress('RM6 6LS' + ', UK');
codeAddress('S25 3QZ' + ', UK');
codeAddress('WC2H 7LR' + ', UK');
codeAddress('BH24 1DW' + ', UK');
codeAddress('EC2N 6AR' + ', UK');
codeAddress('W1U 2FA' + ', UK');
codeAddress('B60 3DX' + ', UK');    
}

  function codeAddress(vPostCode) {
if (geocoder) {
  geocoder.geocode( { 'address': "'" + vPostCode + "'"}, function(results, status) {
    if (status == google.maps.GeocoderStatus.OK) {
      map.setCenter(results[0].geometry.location);
      var marker = new google.maps.Marker({
          map: map, 
          position: results[0].geometry.location
      });
    } else {
      alert("Geocode was not successful for the following reason: " + status);
    }
  });
}
}

</script>
<body style="margin:0px; padding:0px;" onload="initialize()">
<div id="map_canvas" style="width:100%; height:90%"></div>
</body>

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编辑:这是我试图让它在相关部分暂停/等待,但它没有做任何事情:

function codeAddress(vPostCode) {
    if (geocoder) {
    while (wait) { /* Just wait. */ };
      geocoder.geocode( { 'address': "'" + vPostCode + "'"}, function(results, status) {
        if (status == google.maps.GeocoderStatus.OK) {
          map.setCenter(results[0].geometry.location);
          var marker = new google.maps.Marker({
              map: map, 
              position: results[0].geometry.location
          });
        /* When geocoding "fails", see if it was because of over quota error: */
        } else if (status == google.maps.GeocoderStatus.OVER_QUERY_LIMIT) { 
        wait = true;
        setTimeout("wait = true", 2000);
        //alert("OQL: " + status);
        } else {
          alert("Geocode was not successful for the following reason: " + status);
        }
      });
    }
  }

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Answer 1

And*_*ach 41

Mike Williams的教程中没有出现这两行的内容:

    wait = true;
    setTimeout("wait = true", 2000);

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这是一个版本3端口:

http://acleach.me.uk/gmaps/v3/plotaddresses.htm

代码的相关位是

  // ====== Geocoding ======
  function getAddress(search, next) {
    geo.geocode({address:search}, function (results,status)
      { 
        // If that was successful
        if (status == google.maps.GeocoderStatus.OK) {
          // Lets assume that the first marker is the one we want
          var p = results[0].geometry.location;
          var lat=p.lat();
          var lng=p.lng();
          // Output the data
            var msg = 'address="' + search + '" lat=' +lat+ ' lng=' +lng+ '(delay='+delay+'ms)<br>';
            document.getElementById("messages").innerHTML += msg;
          // Create a marker
          createMarker(search,lat,lng);
        }
        // ====== Decode the error status ======
        else {
          // === if we were sending the requests to fast, try this one again and increase the delay
          if (status == google.maps.GeocoderStatus.OVER_QUERY_LIMIT) {
            nextAddress--;
            delay++;
          } else {
            var reason="Code "+status;
            var msg = 'address="' + search + '" error=' +reason+ '(delay='+delay+'ms)<br>';
            document.getElementById("messages").innerHTML += msg;
          }   
        }
        next();
      }
    );
  }

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Answer 2

geo*_*zip 9

这个问题的一般答案是:

每次加载页面时都不要对已知位置进行地理编码.对它们进行地理编码离线并使用生成的坐标在页面上显示标记.

限制存在是有原因的.

如果您无法离线对位置进行地理编码,请参阅Mike Williams的v2教程中的此页面(第17部分地理编码多个地址),该教程描述了一种方法,即v3 API的端口.

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