Spa*_*Dog 6 iphone objective-c ipad ios
我正在尝试实现Apple发布的新VerificationController.m类来修复应用内购买欺诈问题.
正如Apple发布的所有内容一样,这是一个更加模糊,不完整和糟糕的解释文档,其中包含大量空洞和未知数,无法被每个人所规避/理解.
我试图实现它,但在代码的最后我们看到这四种方法:
- (NSString *)encodeBase64:(const uint8_t *)input length:(NSInteger)length
{
#warning Replace this method.
return nil;
}
- (NSString *)decodeBase64:(NSString *)input length:(NSInteger *)length
{
#warning Replace this method.
return nil;
}
#warning Implement this function.
char* base64_encode(const void* buf, size_t size)
{ return NULL; }
#warning Implement this function.
void * base64_decode(const char* s, size_t * data_len)
{ return NULL; }
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你可以看到Apple懒得在代码末尾实现C函数.由于我的C/C++能力很糟糕,我发现我需要在C/C++中实现这两个函数,并且它们必须返回char和void(???).其他人已经发布了在SO上执行此操作的例程,但是他们要么在Objective-C中,要么不返回chars和void(??).
注意:这是我遇到的另一个问题:如果Apple以这种形式使用该方法,该方法如何返回void?
uint8_t *purchase_info_bytes = base64_decode([purchase_info_string cStringUsingEncoding:NSASCIIStringEncoding], &purchase_info_length);
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不应该返回uint8_t吗?
注意2:我遇到的另一个问题是apple表示base64_encode是必需的,但它没有在它们提供的代码上使用.我认为他们吸烟不好或我的C/C++知识真的很臭.
所以,回到我的第一个问题.有人可以发布/指出一个方法,可以完成遵循声明的方法base64_encode和base64_decode的要求的工作吗?请不要发布与Apple强加的这些要求不兼容的objective-c方法.
谢谢.
这个解决方案应该非常简单,其中包括填充缺失信息的所有方法.在沙箱中进行测试和功能.
// single base64 character conversion
static int POS(char c)
{
if (c>='A' && c<='Z') return c - 'A';
if (c>='a' && c<='z') return c - 'a' + 26;
if (c>='0' && c<='9') return c - '0' + 52;
if (c == '+') return 62;
if (c == '/') return 63;
if (c == '=') return -1;
[NSException raise:@"invalid BASE64 encoding" format:@"Invalid BASE64 encoding"];
return 0;
}
- (NSString *)encodeBase64:(const uint8_t *)input length:(NSInteger)length
{
return [NSString stringWithUTF8String:base64_encode(input, (size_t)length)];
}
- (NSString *)decodeBase64:(NSString *)input length:(NSInteger *)length
{
size_t retLen;
uint8_t *retStr = base64_decode([input UTF8String], &retLen);
if (length)
*length = (NSInteger)retLen;
NSString *st = [[[NSString alloc] initWithBytes:retStr
length:retLen
encoding:NSUTF8StringEncoding] autorelease];
free(retStr); // If base64_decode returns dynamically allocated memory
return st;
}
char* base64_encode(const void* buf, size_t size)
{
static const char base64[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
char* str = (char*) malloc((size+3)*4/3 + 1);
char* p = str;
unsigned char* q = (unsigned char*) buf;
size_t i = 0;
while(i < size) {
int c = q[i++];
c *= 256;
if (i < size) c += q[i];
i++;
c *= 256;
if (i < size) c += q[i];
i++;
*p++ = base64[(c & 0x00fc0000) >> 18];
*p++ = base64[(c & 0x0003f000) >> 12];
if (i > size + 1)
*p++ = '=';
else
*p++ = base64[(c & 0x00000fc0) >> 6];
if (i > size)
*p++ = '=';
else
*p++ = base64[c & 0x0000003f];
}
*p = 0;
return str;
}
void* base64_decode(const char* s, size_t* data_len_ptr)
{
size_t len = strlen(s);
if (len % 4)
[NSException raise:@"Invalid input in base64_decode" format:@"%d is an invalid length for an input string for BASE64 decoding", len];
unsigned char* data = (unsigned char*) malloc(len/4*3);
int n[4];
unsigned char* q = (unsigned char*) data;
for(const char*p=s; *p; )
{
n[0] = POS(*p++);
n[1] = POS(*p++);
n[2] = POS(*p++);
n[3] = POS(*p++);
if (n[0]==-1 || n[1]==-1)
[NSException raise:@"Invalid input in base64_decode" format:@"Invalid BASE64 encoding"];
if (n[2]==-1 && n[3]!=-1)
[NSException raise:@"Invalid input in base64_decode" format:@"Invalid BASE64 encoding"];
q[0] = (n[0] << 2) + (n[1] >> 4);
if (n[2] != -1) q[1] = ((n[1] & 15) << 4) + (n[2] >> 2);
if (n[3] != -1) q[2] = ((n[2] & 3) << 6) + n[3];
q += 3;
}
// make sure that data_len_ptr is not null
if (!data_len_ptr)
[NSException raise:@"Invalid input in base64_decode" format:@"Invalid destination for output string length"];
*data_len_ptr = q-data - (n[2]==-1) - (n[3]==-1);
return data;
}
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