1 c++ collision-detection sqrt
好吧,我需要做一个碰撞测试.这种方式似乎最简单,但我的编译器并不这么认为.谢谢你的回复!
C++代码:
int sqrd(int num) { return (num*num); } //squares a number
bool checkColShip() {
for(int x = 0;x < 10;x++) {
double distance = 0; //use to be int tried to change it
distance = abs( sqrt( sqrd((one.getXPos() - asteroid[x].getXPos()) +
sqrd((one.getYPos() - asteroid[x].getYPos()))
); //include cmath
distance -= 20;//ship radius
distance -= 20;//asteroid radius
if (distance<=0) return true;//collision true
}
//no collision
return false;
}
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编译错误:
c:\documents and settings\all users\documents\c++ projects\learn sdl\learn sdl\main.cpp(702): error C2668: 'sqrt' : ambiguous call to overloaded function
c:\program files\microsoft visual studio 10.0\vc\include\math.h(589): could be 'long double sqrt(long double)'
c:\program files\microsoft visual studio 10.0\vc\include\math.h(541): or 'float sqrt(float)'
c:\program files\microsoft visual studio 10.0\vc\include\math.h(127): or 'double sqrt(double)'
while trying to match the argument list '(int)'
========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========
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PS我通常缩进我的代码,但第一次在这里发帖,它一直给我带来问题.
错误是说有三个可用的sqrt()功能,传递它时没有明显的选择int.
如果你愿意,你必须决定float或double或long double铸造参数.
与您的问题无关 - 您的代码总是传递一个真实的非负数sqrt(),因此平方根将始终是真实的非负数.传递结果abs()是不必要的.