展开/折叠具有嵌套行的表行

Question

我想创建一个具有以下结构的表:
Row1 datacolumn1 datacolumn2 datacolumn2
SubRow1 datacolumn1 datacolumn2 datacolumn2
SubRow2 datacolumn1 datacolumn2 datacolumn2
SubRow3 datacolumn1 datacolumn2 datacolumn2

我想在点击时展开/折叠子行.我似乎无法让它与表格一起使用.我知道列表是一个更好的选择,但表格更容易维护.

<tbody>
    <tr class="row1 head1">
        <td>Cash and Equivalents</td>
        <td>000,000</td>
        <td>000,000</td>

    </tr>
    <tr class="row1 head2 closed">
        <td>Cash and Equivalents</td>
        <td>000,000</td>
        <td>000,000</td>

    </tr>
    <tr class="row1 head3">
        <td>Cash and Equivalents</td>
        <td>000,000</td>
        <td>000,000</td>

    </tr>
    <tr class="row1 head4">
        <td>Cash and Equivalents</td>
        <td>000,000</td>
        <td>000,000</td>

    </tr>
    <tr class="row1 head5">
        <td>Cash and Equivalents</td>
        <td>000,000</td>
        <td>000,000</td>

    </tr>
    <tr class="row2 head1">
        <td>Cash and Equivalents</td>
        <td>000,000</td>
        <td>000,000</td>

    </tr>

    <tr class="row2 head4">
        <td>Cash and Equivalents</td>
        <td>000,000</td>
        <td>000,000</td>

    </tr>
    <tr class="row2 head5">
        <td>Cash and Equivalents</td>
        <td>000,000</td>
        <td>000,000</td>

    </tr>
    <tr>
        <td>Cash and Equivalents</td>
        <td>000,000</td>
        <td>000,000</td>

    </tr>
    <tr>
        <td>Cash and Equivalents</td>
        <td>000,000</td>
        <td>000,000</td>

    </tr>

</tbody>

在行上单击,我调用以下函数:

holdingsTree: function(that){
    var stack = '',
        classes = ba.splitClasses(that.attr('class')),
        nextRow = ba.getClassNumber(classes[1], "head");

    if (that.next().hasClass('head'+nextRow)){
        if (that.next().hasClass(classes[0]) && that.next().hasClass('open')){
            that.nextUntil('.head1').hide().addClass('closed').removeClass('open');
        } else if (that.next().hasClass(classes[0])){
            stack = that.nextUntil('.head1');
            $.each(stack, function(i, item){ if ($(item).hasClass('head' + (nextRow))){ $(this).show().addClass('open').removeClass('closed'); } });
        }
    } else if (that.next().hasClass('head'+ (nextRow+1))){
        if (that.next().hasClass(classes[0]) && that.next().hasClass('open')){
            that.nextUntil('.head1').hide().addClass('closed').removeClass('open');
        } else if (that.next().hasClass(classes[0])){
            stack = that.nextUntil('.head1');
            $.each(stack, function(i, item){ if ($(item).hasClass('head' + (nextRow+1))){ $(this).show().addClass('open').removeClass('closed'); } });
        }
    } else if (that.next().hasClass('head'+ (nextRow+2))){
        if (that.next().hasClass(classes[0]) && that.next().hasClass('open')){
            that.nextUntil('.head1').hide().addClass('closed').removeClass('open');
            return;
        } else if (that.next().hasClass(classes[0])){
            stack = that.nextUntil('.head'+ (nextRow+3));
            $.each(stack, function(i, item){ if ($(item).hasClass('head' + (nextRow+2))){ $(this).show().addClass('open').removeClass('closed'); } });
            //stack.find('.head'+(nextRow+2)).show().addClass('open').removeClass('closed');
        }
    } else if (that.next().hasClass('head'+ (nextRow+3))){
        if (that.next().hasClass(classes[0]) && that.next().hasClass('open')){
            that.nextUntil('.head1').hide().addClass('closed').removeClass('open');
        } else if (that.next().hasClass(classes[0])){
            stack = that.nextUntil('.head1');
            $.each(stack, function(i, item){ if ($(item).hasClass('head' + (nextRow+3))){ $(this).show().addClass('open').removeClass('closed'); } });
        }
    } else if (that.next().hasClass('head'+ (nextRow+4))){
        if (that.next().hasClass(classes[0]) && that.next().hasClass('open')){
            that.nextUntil('.head1').hide().addClass('closed').removeClass('open');
        } else if (that.next().hasClass(classes[0])){
            that.nextUntil('.head1').show().addClass('open').removeClass('closed');
        }
    } 

},

splitClasses: function(names){
    var names = names.split(' ');
    return names;
},

getClassNumber: function(name, pretext){
    var result = name.split(pretext);
    console.log(parseInt(result[1]) + 1);
    return parseInt(result[1]) + 1;
}

这很糟糕.我知道.:)

Answer 1

您可以为您调用父项的行创建一个类,为您调用子项的行创建一个类,并切换它们的显示.

这是如何做:

$(document).ready(function() {

    function getChildren($row) {
        var children = [];
        while($row.next().hasClass('child')) {
             children.push($row.next());
             $row = $row.next();
        }            
        return children;
    }        

    $('.parent').on('click', function() {

        var children = getChildren($(this));
        $.each(children, function() {
            $(this).toggle();
        })
    });

})

检查这个小提琴的完整运行代码http://jsfiddle.net/T8t2r/3/ 如果这解决了你的问题,请接受答案!

祝好运!

编辑:在更多级别上工作,一种方法是拥有一个级别属性.所以这里是更新版本,应该可以在任意数量的级别上工作.http://jsfiddle.net/T8t2r/9/

$(document).ready(function() {

    function getChildren($row) {
        var children = [], level = $row.attr('data-level');
        while($row.next().attr('data-level') > level) {
             children.push($row.next());
             $row = $row.next();
        }            
        return children;
    }        

    $('.parent').on('click', function() {

        var children = getChildren($(this));
        $.each(children, function() {
            $(this).toggle();
        })
    });

})