插入字符串 << 重载 C++ 时出错

Question

我正在尝试在 C++ 中的类上重载 << 运算符。每当我将普通字符串（例如“”）插入输出流时，我都会收到无法理解的编译错误。我以前做过一次，没有任何问题，所以我很困惑。

friend std::ostream& operator<<(std::ostream& out, Variable v);

std::ostream& operator<<(std::ostream& out, Variable v) {
    out << v.type;
    out << " ";
    out << v.name;
    return out;
}

这是输出：

src/Variable.cpp: In function 'std::ostream& operator<<(std::ostream&, Variable)':
src/Variable.cpp:35:9: error: no match for 'operator<<' in 'out << " "'
src/Variable.cpp:35:9: note: candidates are:
src/Variable.cpp:33:15: note: std::ostream& operator<<(std::ostream&, Variable)
src/Variable.cpp:33:15: note:   no known conversion for argument 2 from 'const char [2]' to 'Variable'
In file included from /usr/local/Cellar/gcc/4.7.0/gcc/lib/gcc/x86_64-apple-darwin10.8.0/4.7.0/../../../../include/c++/4.7.0/string:54:0,
             from src/../inc/Variable.h:4,
             from src/Variable.cpp:1:
/usr/local/Cellar/gcc/4.7.0/gcc/lib/gcc/x86_64-apple-darwin10.8.0/4.7.0/../../../../include/c++/4.7.0/bits/basic_string.h:2750:5: note: template<class _CharT, class _Traits, class _Alloc> std::basic_ostream<_CharT, _Traits>& std::operator<<(std::basic_ostream<_CharT, _Traits>&, const std::basic_string<_CharT, _Traits, _Alloc>&)
/usr/local/Cellar/gcc/4.7.0/gcc/lib/gcc/x86_64-apple-darwin10.8.0/4.7.0/../../../../include/c++/4.7.0/bits/basic_string.h:2750:5: note:   template argument deduction/substitution failed:
src/Variable.cpp:35:9: note:   mismatched types 'const std::basic_string<_CharT, _Traits, _Alloc>' and 'const char [2]'
make: *** [bin/Variable.o] Error 1

Answer 1

德普。我没有包含 iostream。然而，这对我来说没有多大意义......因为每当我没有向 ostream 添加字符串时它就会起作用。我认为编译器根本无法找到 ostream，并且会抱怨这一点