是"继续"Pythonic的方式逃离try catch块吗？

Question

我是django的新手,想到了简单的django应用程序以了解它的更多信息,在代码中的一个地方我必须选择locationName并获得与locationName表中相同id的元素.当我开始想知道是continue逃避for循环的最pythonic方式？

有问题的代码如下:

for locationName in locationGroup:
    idRef = locationName.id
    try:
        element = location.objects.order_by('-id').filter(name__id=idRef)[0]
    except IndexError:
        continue

Answer 1

如果有一些代码你不想在except子句之后执行,那么它continue是完全有效的,否则有些代码可能会pass更合适.

for x in range(y):
    try:
        do_something()
    except SomeException:
        continue
    # The following line will not get executed for the current x value if a SomeException is raised
    do_another_thing() 

for x in range(y):
    try:
        do_something()
    except SomeException:
        pass
    # The following line will get executed regardless of whether SomeException is thrown or not
    do_another_thing()