如何将嵌套字典展平为一些对象的列表(SomeObject在下面的示例中)应该包含这些字典的键?
例如:让我们有一个以下类型的字典
var nestedDictionary = new Dictionary<int, Dictionary<int, string>>();
Run Code Online (Sandbox Code Playgroud)
那么,让我们来上课吧
public class SomeObject
{
public int var1;
public int var2;
public string someStringVar;
}
Run Code Online (Sandbox Code Playgroud)
如何转换nestedDictionary为List<SomeObject>where var1是外部字典var2的键,是内部字典的键,是内部字典someStringVar的字符串值?
基本上,我该如何转移:
nestedDict[0][0] = "foo";
nestedDict[0][1] = "bar";
nestedDict[0][2] = "foo1";
nestedDict[1][0] = "bar1";
nestedDict[1][1] = "foo2";
nestedDict[1][2] = "bar2";
Run Code Online (Sandbox Code Playgroud)
对此(在伪C#中只是为了可视化)
objList[0] = SomeObject { var1 = 0, var2 = 0, someStringVar = "foo" }
objList[1] = SomeObject { var1 = 0, var2 = 1, someStringVar = "bar" }
objList[2] = SomeObject { var1 = 0, var2 = 2, someStringVar = "foo1" }
objList[3] = SomeObject { var1 = 1, var2 = 0, someStringVar = "bar1" }
objList[4] = SomeObject { var1 = 1, var2 = 1, someStringVar = "foo2" }
objList[5] = SomeObject { var1 = 1, var2 = 2, someStringVar = "bar2" }
Run Code Online (Sandbox Code Playgroud)
使用LINQ?
Fré*_*idi 11
您可以使用SelectMany()并编写如下内容:
var objList = nestedDictionary.SelectMany(
pair => pair.Value.Select(
innerPair => new SomeObject() {
var1 = pair.Key,
var2 = innerPair.Key,
someStringVar = innerPair.Value
})).ToList();
Run Code Online (Sandbox Code Playgroud)
这应该工作:
var flattened =
from kvpOuter in nestedDictionary
from kvpInner in kvpOuter.Value
select new SomeObject()
{
var1 = kvpOuter.Key,
var2 = kvpInner.Key,
someStringVar = kvpInner.Value
};
var list = flattened.ToList(); // if you need a list...
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
3205 次 |
| 最近记录: |