使用POST参数通过UIWebView加载网页

Question

是否可以通过带有POST参数的UIWebView加载页面？我可能只是加载带有参数的嵌入表单并用javascript填充它们并强制提交,但是有更清洁和更快的方法吗？

谢谢!

Answer 1

创建POST URLRequest并使用它来填充webView

NSURL *url = [NSURL URLWithString: @"http://your_url.com"];
NSString *body = [NSString stringWithFormat: @"arg1=%@&arg2=%@", @"val1",@"val2"];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc]initWithURL: url];
[request setHTTPMethod: @"POST"];
[request setHTTPBody: [body dataUsingEncoding: NSUTF8StringEncoding]];
[webView loadRequest: request];

Answer 2

以下是内容类型为x-www-form-urlencoded的Web视图POST调用示例.

您需要更改其他内容类型的postData.

对于Swift 3

let url = NSURL (string: "https://www.google.com")
let request = NSMutableURLRequest(URL: url!)
request.HTTPMethod = "POST"
request.addValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")

let post: String = "sourceId=44574fdsf01e-e4da-4e8c-a897-17722d00e1fe&sourceType=abc"
let postData: NSData = post.dataUsingEncoding(NSASCIIStringEncoding, allowLossyConversion: true)!

request.HTTPBody = postData
webView.loadRequest(request)

对于Swift 4

let url = URL (string: "let url = NSURL (string: "https://www.google.com")
let request = NSMutableURLRequest(url: url!)
request.httpMethod = "POST"
request.addValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")

let post: String = "sourceId=44574fdsf01e-e4da-4e8c-a897-17722d00e1fe&sourceType=abc"
let postData: Data = post.data(using: String.Encoding.ascii, allowLossyConversion: true)!

request.httpBody = postData
webView.load(request as URLRequest)

Answer 3

来自oxigen的答案只是一个微小的变化.使用时:

NSString *theURL = @"http://your_url.com/sub";
...//and later
[request setURL:[NSURL URLWithString:theURL]];

它没有工作,无论是作为GET还是POST请求,都为它工作的URL添加了一个结束斜杠.

NSString *theURL = @"http://your_url.com/sub/";