SQL - 选择具有最大值的所有行

Question

我有这个SQL查询:

SELECT id, COUNT(*) AS price
FROM (SELECT * FROM rt WHERE somecondition) AS st
      JOIN tt
      ON st.id = tt.id
GROUP BY id;

现在,我想选择具有该表最高价格的所有行.我试过这个,遗憾的是根本没有返回任何行:

SELECT id, COUNT(*) AS price
FROM (SELECT * FROM rt WHERE somecondition) AS st
      JOIN tt
      ON st.id = tt.id
GROUP BY id
HAVING price = MAX(price);

我有点失落,有没有人有任何指针？

Answer 1

HAVING用于在聚合发生后检查条件。

WHERE在聚合发生之前使用。

SELECT id, COUNT(*) AS price
FROM (SELECT * FROM rt WHERE somecondition) AS st
  JOIN tt
  ON st.id = tt.id
WHERE price = (SELECT MAX(price) FROM ...table)
GROUP BY id