cpp*_*pit 3 php mysql sql select
这是我的代码:
$sqlz = "SELECT t1.user_id, t2.status, t2.email
FROM coverages t1
LEFT JOIN users t2 ON t1.user_id = t2.user_id
GROUP BY t1.user_id
HAVING COUNT(t1.user_id) =".$value;
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我想添加这个" WHERE users.email IS NOT NULL"当我添加它时,它返回一个白页/没有结果.据我所知,db上至少有200个结果,其中包含一封电子邮件,并且符合该条件.
这是我所做的不起作用的一个例子:
$sqlz = "SELECT t1.user_id, t2.status, t2.email
FROM coverages t1
LEFT JOIN users t2 ON t1.user_id = t2.user_id
WHERE users.email IS NOT NULL
GROUP BY t1.user_id
HAVING COUNT(t1.user_id) =".$value;
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Joh*_*Woo 15
我认为你需要使用t2(别名)而不是users.
$sqlz = "SELECT t1.user_id, t2.status, t2.email
FROM coverages t1
LEFT JOIN users t2 ON t1.user_id = t2.user_id
WHERE t2.email IS NOT NULL
GROUP BY t1.user_id
HAVING COUNT(t1.user_id) = " .$value;
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